I think the shaded region for this problem will the part of the circle that is not covered by the triangle. First, determine the area of the circle by the equation,
A = πD²/4
Substituting the given diameter,
A = π(16 ft)²/4 = 200.96 ft²
Then, determine the area of the triangle with the equation,
A = bh/2
Since the base of the triangle is the diameter, b = 16 ft. Then, its height will be half the height and that will be equal to 8 ft. Substituting,
A = (16 ft)(8 ft) / 2 = 64 ft²
The difference between the two areas is 136.96 ft².
Answer:
x=3,y=0
x=-1,y=0
Step-by-step explanation:
We will have to factorise to get the value of x before solving for y
Let's solve
y=x^2-2x-3
To factorise x
x^2-3x+x-3
x(x-3)+1(x-3)
(x-3)+(x+1)
x-3=0
x=3
x+1=0
x=-1
Let's substitute the value of value to get the value for y
y=x^2-2x-3
When x is 3
y=3^2-2(3)-3
y=9-6-3
y=0
When x is-1
y=(-1)^2-2(-1)-3
y=1+2-3
y=0
Therefore when x is 3,y is 0
When x is -1,y is 0
The first two teams have a 3 to 2 ratio
Answer:
y=-8
Step-by-step explanation:
-8y-16=48
+16+16
-8y=64
y=-8
