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Makovka662 [10]
3 years ago
13

B) After allowing 16 % discount on the marked price of an article and levying 13 % value

Mathematics
1 answer:
aksik [14]3 years ago
7 0

Answer:

135.15

Step-by-step explanation:

let SP be x

sp with vat=sp + vat % of sp

9492=x+13/100*x

x=1039.6

vat=vat% of sp

=13/100*1039.6

=135.15

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What work do i need to show?
stealth61 [152]
You have to show finding the square root of it ______        ___       __
                                                                       √144x^2  +  √225  =  √0
which will give you 12x+15=0
12x=15
x=5/4
4 0
3 years ago
X-2(x+10)=12 , -15=5(3q-10)-5q <br><br> Please Help
Rashid [163]

Answer:

-4,3.5

Step-by-step explanation:

1st one

x-2x-20 = 12

-x = 32

x=-4

2nd one

-15=15q-50 - 5q

35= 10q

q = 3.5

3 0
3 years ago
An account earns simple interest. $1800 at 6.5% for 30 months Find the interest earned.
horrorfan [7]
Okay. The formula for simple interest is prt. You multiply the principal (initial amount) by the rate (percentage) by the time (months or years). $1,800 is the principal and 6.5% is the percentage rate. 1,800 * 6.5% (0.065) is 117. You earn $117 in interest annually. The time period is 30 months. There are 12 months in 1 year. Divide the amount of months by 12 to put it in a decimal. 30/12 is 2.5. Now, multiply 117 by 2.5 to find the total amount of interest earned. 117 * 2.5 is 292.5. There. The total amount of interest earned is $292.50.
4 0
3 years ago
Pls help me with 4 , 5 , and 6 and show me how you did it i will mark brainlist !!
LuckyWell [14K]

Answer:

2 on top and bottom of 4   5 is 3 on top and bottom      and lastly 6 is 8 on top and bottom.

Step-by-step explanation:

all you have to do is divide the two bottom numbers on each problem and the answer to the problem will be the same on top and bottom

3 0
3 years ago
Businesses deposit large sums of money into bank accountsImagine an account with $10 million dollars in it.
adoni [48]

again, let's assume daily compounding means 365 days per year.

~~~~~~ \textit{Simple Interest Earned} \\\\ I = Prt\qquad \begin{cases} I=\textit{interest earned}\\ P=\textit{original amount deposited}\dotfill & \$10000000\\ r=rate\to 2.12\%\to \frac{2.12}{100}\dotfill &0.0212\\ t=years\dotfill &1 \end{cases} \\\\\\ I = (10000000)(0.0212)(1)\implies \boxed{I=212000}

~~~~~~ \textit{Compound Interest Earned Amount} \\\\ A=P\left(1+\frac{r}{n}\right)^{nt} \quad \begin{cases} A=\textit{accumulated amount}\\ P=\textit{original amount deposited}\dotfill &\$10000000\\ r=rate\to 2.12\%\to \frac{2.12}{100}\dotfill &0.0212\\ n= \begin{array}{llll} \textit{times it compounds per year}\\ \textit{daily, thus 365} \end{array}\dotfill &365\\ t=years\dotfill &1 \end{cases}

A=10000000\left(1+\frac{0.0212}{365}\right)^{365\cdot 1}\implies A\approx 10214256.88 \\\\\\ \underset{\textit{earned interest amount}}{10214256.88~~ - ~~10000000 ~~ \approx ~~ \boxed{214256.88}}

what's their difference?  well

\stackrel{\textit{compounded daily}}{\approx 214256.88}~~ - ~~\stackrel{\textit{simple interest}}{212000}\implies \boxed{2256.88}

7 0
2 years ago
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