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denis-greek [22]
3 years ago
9

Can someone pleeeeeas helpp mehh it is I-Ready!!!!!​

Mathematics
1 answer:
Georgia [21]3 years ago
4 0

Answer:

the answer to the question is (20,5

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--The sum of two numbers is 33. One number is 2 times as large as the other. What are the numbers?​
frozen [14]

Answer:

11 and 22

Step-by-step explanation:

Let x be the first number

the second number is twice the first one so it's 2x

The equation is

  • 2x+x =33
  • 3x = 33             divide by 3 in each side
  • x = 33/3
  • x= 11

so the first number is 11 and the second one 22 (11*2)

4 0
4 years ago
Read 2 more answers
Simplify ten to the sixth divided by ten to the negative third.
Andrews [41]
Exponential rules state that when you divide exponents, you subtract by the powers. The powers have the same coefficients, so you can divide the two numbers.

6 - (-3) = 9

The answer is 10^9.
4 0
3 years ago
Read 2 more answers
Find the indicated probability or percentage for the sampling error. The distribution of weekly salaries at a large company is r
Flauer [41]

Answer:

The probability that the sampling error made in estimating the mean weekly salary for all employees of the company by the mean of a random sample of weekly salaries of 80 employees will be at most $75 is 0.9297.

Step-by-step explanation:

According to the Central Limit Theorem if we have a non-normal population with mean <em>μ</em> and standard deviation <em>σ</em> and appropriately huge random samples (<em>n</em> > 30) are selected from the population with replacement, then the distribution of the sample means will be approximately normally distributed.

Then, the mean of the distribution of sample means is given by,

\mu_{\bar x}=\mu

And the standard deviation of the distribution of sample means is given by,

\sigma_{\bar x}=\frac{\sigma}{\sqrt{n}}

The information provided is:

\mu=\$1000\\\sigma=\$370\\n=80

As <em>n</em> = 80 > 30, the central limit theorem can be used to approximate the sampling distribution of sample mean weekly salaries.

Let \bar X represent the sample mean weekly salaries.

The distribution of \bar X is: \bar X\sim N(\$1000,\ \$41.37)

Now we need to compute the probability of the sampling error made in estimating the mean weekly salary to be at most $75.

The sampling error is the the difference between the estimated value of the parameter and the actual value of the parameter, i.e. in this case the sampling error is, |\bar X-\mu|= 75.

Compute the probability as follows:

P(-75

                                     =P(-1.81

Thus, the probability that the sampling error made in estimating the mean weekly salary for all employees of the company by the mean of a random sample of weekly salaries of 80 employees will be at most $75 is 0.9297.

3 0
3 years ago
I'm even more confused now... now which is bigger one hundred fifty-eight thousandths or 0.58 plsssss help me!!!!!
hram777 [196]

Answer:

0.58 is larger

Step-by-step explanation:

3 0
3 years ago
Read 2 more answers
An object launched vertically from a point that is 37.5 feet above ground level with an initial velocity of 48.6 feet per second
Elis [28]

Answer: 3.675 seconds

Step-by-step explanation:

Hi, when the object hits the ground, h=0:

h=−16t^2+48.6t+37.5

0=−16t^2+48.6t+37.5

We have to apply the quadratic formula:  

For: ax2+ bx + c  

x =[ -b ± √b²-4ac] /2a  

Replacing with the values given:  

a=-16 ; b=48.6; c=37.5

x =[ -(48.6) ± √(-48.6)²-4(-16)37.5] /2(-16)  

x = [ -48.6 ± √ 4,761.96] /-32

x = [ -48.6 ± 69] /-32

Positive:  

x = [ -48.6 + 69] /-32 = -0.6375

Negative:  

x = [ -48.6 - 69] /-32 = 3.675 seconds (seconds can't be negative)

Feel free to ask for more if needed or if you did not understand something.  

8 0
3 years ago
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