Answer:
Minimum length of rope needed to span the sides of the prism is 10 units.
Step-by-step explanation:
Let us draw a perpendicular from apex to base BC,Let it be AD since ΔABC is isosceles triangle, that perpendicular will touch mid of base. That is BD=DC=
=3
Now we know the angle m∠ABC as 53.13°.
From ΔADC, 

≈10
Hence minimum length of rope needed to span the sides of prism is 10 units.
68.0052/12 would be 5.6671. If you round that to the nearest hundredth it would be 5.67. Hope this helps!
You can solve this problem with one variable, x.
If the helicopter flew 34 times on Friday, and an equal number of times on Saturday and Sunday, then you can use the equation:
34+2x=118
2x=84
x=42
The answer is B.
Hope this helps!
-Astro, Helper in Training
Answer:
13.18% or 0.1318
Step-by-step explanation:
please see the attached files for explanation
Answer:
The answer would be 10 for the slope
Step-by-step explanation: