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Alchen [17]
3 years ago
5

A proper fraction never has the same value as a mixed number.

Mathematics
1 answer:
Ksju [112]3 years ago
8 0
This statement is false: 3 and one half is the same as 7/2
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Y−3=−1/2(x+4) I need help
frozen [14]

Answer: The slope is - 1/2.

Step-by-step explanation:

4 0
3 years ago
Fewer young people are driving. In year A, 67.9% of people under 20 years old who were eligible had a driver's license. Twenty y
aleksley [76]

Answer:

                                 Case a                               Case b

margin of error       0.0216                                   0.0231

Interval estimate   (0.7016 , 0.6795)                (0.5031 , 0.4569)

margin of error is not same in both cases.

Step-by-step explanation:

a

At 95% confidence interval the interval estimate of number of 20 year old drivers in year A can be computed as

  p'  ±  z  \sqrt{\frac{p'(1-p')}{n} }

= 0.68 ± 1.96 \sqrt{\frac{0.68(1-0.68)}{1800} }

= 0.7016 , 0.6795

the margin of error can be written as

z  \sqrt{\frac{p'(1-p')}{n} }

= 1.96 \sqrt{\frac{0.68(1-0.68)}{1800} }

= 0.0216

b

At 95% confidence interval the interval estimate of number of 20 year old drivers in year B can be computed as

p'  ±  z  \sqrt{\frac{p'(1-p')}{n} }

= 0.48 ± 1.96 \sqrt{\frac{0.48(1-0.48)}{1800} }

=  0.5031 , 0.4569

the margin of error can be written as

z  \sqrt{\frac{p'(1-p')}{n} }

=  1.96 \sqrt{\frac{0.48(1-0.48)}{1800} }

= 0.0231

c

Sample size is same in case A and B but proportion is different in both cases so margin of error is different in both cases

3 0
3 years ago
I just made a purchase of $130.00 but once I got my car and looked at the receipt, I realized the salesperson who helped me did
Andrej [43]

Answer:

Guessing you want me to figure out what your cost should have been. On it!

Step-by-step explanation:

130 * .15 = 19.5

130 - 19.5 = $110.5

That should be the new cost.

5 0
2 years ago
Pls help <br> It due asap <br> Ydydbdbgdbs
Temka [501]

Answer:

1 & 7

2 & 8

5 & 3

6 & 4

Step-by-step explanation:

5 0
3 years ago
Read 2 more answers
A certain system has two components. There are 6 different models of the first component and 10 different models of the second.
Alisiya [41]

Answer: 1800

Step-by-step explanation:

Given : A certain system has two components.

Number of different models of the first component = 6

Number of different models of the second component  = 10

A salesman must select 2 of the first component and 3 of the second to take on a sales call , so we use combinations ( ∵ order of selection not matters)

The number of different sets of components can the salesman take = ^{6}C_2\times^{10}C_3

\dfrac{6!}{2!(6-2)!}\times\dfrac{10!}{3!(10-3)!}\ \ [\because\ ^nC_r=\dfrac{n!}{r!(n-r)!}]    

=1800

Hence, the number of different sets of components can the salesman take = 1800

8 0
4 years ago
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