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natita [175]
3 years ago
13

Please help!!! Please help me! This is due tomorrow and I really need some help! Thank you.

Mathematics
1 answer:
grandymaker [24]3 years ago
6 0

Answer:

<em>o</em><em>k</em><em> </em><em>i</em><em>'</em><em>l</em><em>l</em><em> </em><em>h</em><em>e</em><em>l</em><em>p</em><em> </em><em>u</em><em> </em><em>s</em><em>a</em><em>y</em><em> </em><em>t</em><em>h</em><em>a</em><em>n</em><em>k</em><em>y</em><em>u</em><em> </em><em>t</em><em>o</em><em> </em><em>m</em><em>e</em><em>!</em><em>!</em><em>!</em><em>o</em><em>s</em><em>h</em><em>i</em><em>e</em><em>e</em>

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10^3=10*10*10=1000
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3 years ago
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<img src="https://tex.z-dn.net/?f=%20%5Clarge%7B%5Cbold%20%5Cred%7B%20%5Csum%20%5Climits_%7B8%7D%5E%7B4%7D%20%7Bx%7D%5E%7B2%7D%2
kiruha [24]

Answer:

No solution

Step-by-step explanation:

We have

$\sum_{x=8}^{4}x^2 + 9\left(\dfrac{\cos^2(\infty)}{\sin^2(\infty)} \right)$

For the sum it is not correct to assume

$\sum_{x=8}^{4}x^2= 8^2 + 7^2+6^2+5^2+4^2 = 64+49+36+25+16 = 190$

Note that for

$\sum_{x=a}^b f(x)$

it is assumed a\leq x \leq b and in your case \nexists x\in\mathbb{Z}: a\leq x\leq b for a>b

In fact, considering a set S we have

$\sum_{x=a}^b (S \cup \varnothing) = \sum_{x=a}^b S + \sum_{x=a}^b \varnothing $ that satisfy S = S \cup \varnothing

This means that, by definition \sum_{x=a}^b \varnothing = 0

Therefore,

$\sum_{x=8}^{4}x^2 = 0$

because the sum is empty.

For

9\left(\dfrac{\cos^2(\infty)}{\sin^2(\infty)} \right)

we have other problems. Actually, this case is really bad.

Note that \cos^2(\infty) has no value. In fact, if we consider for the case

$\lim_{x \to \infty} \cos^2(x)$, the cosine function oscillates between [-1, 1] , and therefore it is undefined. Thus, we cannot evaluate

9\left(\dfrac{\cos^2(\infty)}{\sin^2(\infty)} \right)

and then

$\sum_{x=8}^{4}x^2 + 9\left(\dfrac{\cos^2(\infty)}{\sin^2(\infty)} \right)$

has no solution

7 0
3 years ago
(2x-3)^5 please I need it fast thank you.
exis [7]
2x = 5 + 3
2x = 8
x = 8/2
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3 years ago
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Tatiana [17]

Answer:

Correct (192)

Step-by-step explanation:

The formula for a parallelogram's area is just base times height. 16x12 is equal to 192, so you are correct.

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2 years ago
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