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svp [43]
2 years ago
13

(2x-3)^5 please I need it fast thank you.

Mathematics
1 answer:
exis [7]2 years ago
7 0
2x = 5 + 3
2x = 8
x = 8/2
x=4
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Josh is incorrect, he did not examine the expression correctly, therefore his answer was wrong.

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34. Which is the rule for the linear<br> function graphed below?
Ivahew [28]

Answer:

We can note that this part of the graph is a linear function. This means that is has a general form: y = mx + c where m is the slop and c is the y-intercept (value of y at x=0). For the slope, we will use the points (0,2) and (3,5) to calculate it as follows: m = (y2-y1)/(x2-x1) = (5-2)/(3-0) = 1 For the y-intercept, we can note that at x=0, the value of y is 2. This means that the equation of the first part of the graph is: y = x + 2

Read more at Answer.Ya.Guru – https://answer.ya.guru/questions/703068-which-rules-define-the-function-graphed-below.html

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2 years ago
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lutik1710 [3]
The best way to solve this problem is by plugging in each answer choice for both equations and seeing which one works. You can already see that choice A doesn't work because -1 is not greater than or equal to 4. That means you just need to test choices B and C!

Choice B (4, -2)
x + y  \geq 6\\&#10;4 + -2  \geq 6\\&#10;2  \geq  6 &#10;
2 is not greater than or equal to 6, so choice B doesn't work.

Choice C (4, 2)
x + y \geq 6\\ &#10;4 + 2 \geq 6\\ &#10;6 \geq 6 \\\\&#10;x  \geq 4\\&#10;4 \geq 4
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-------

Answer: C) (4, 2)
6 0
2 years ago
Simplify the following algebraic expression:<br> 4+3 [6z - 5(6 +2z)]
Tatiana [17]

\huge\text{Hey there!}

\huge\text{4+3 [6z - 5(6 +2z)]}

\huge\text{4+(3)(6z)+(3)(-5(6+2z))}\\\\\rightarrow\huge\text{4+18z+(-30z)+(-90)}

\huge\text{\bf{Combine the like terms if you have any.}}

\huge\text{Like term \#1: 10z \& -30z}\\\\\\\huge\text{Like term \#2: 4 \& -90}

\huge\text{18z + (-30z) + (4 + (-90))}

\huge\text{18z + (-30z) = -12z}\\\\\\\huge\text{4 + (-90) = -86}

\boxed{\boxed{\huge\text{Answer: -12z + (-86)}}}\huge\checkmark

\text{Good luck on your assignment and enjoy your day!}

~\frak{LoveYourselfFirst:)}

5 0
3 years ago
Read 2 more answers
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