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marusya05 [52]
2 years ago
14

What is the range of 45,72,76,82,82,84,89,90,92

Mathematics
1 answer:
Stella [2.4K]2 years ago
5 0

Answer:

the range is 47!

Step-by-step explanation:

to find the range of a set of numbers, first put the numbers in order from smallest to largest (which is already done) and simply subtract the smallest number from the biggest one!

the smallest being 45 and the highest is 92 in this case! hope this helps

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What is the reason for each step in the solution of the equation?
user100 [1]

Answer in the attachment.

3 0
3 years ago
Solve for x. <br>a.5, <br>b.<br>c.9<br>d.10
Liula [17]
Your proportion should look something like this

\frac{x}{6} =  \frac{6}{4}

After cross multiplication, you should end up with this equation

4x=36

After dividing 4 on both sides, you should get that x=9
6 0
3 years ago
Read 2 more answers
6. An ostrich cannot fly, but it is able to run fast. Suppose an ostrich runs east for 7.95 s and then runs 161 m south, so that
Liula [17]

Answer:

159 m

Step-by-step explanation:

From the information given:

It was stated that if the ostrich ran towards the east direction in 7.95 s, let say the distance from the starting point is O towards the east side E, let called the distance towards the east side to be OE.

Again, the ostrich then runs in the south direction for 161 m, let the distance be OS.

Also, let the magnitude of the resultant displacement between the east direction to the south direction be ES = 226m.

We are to find, the magnitude of the ostrich's eastward component.

i.e. The distance traveled from the center to the east direction within the time frame of 7.95 s.

Using the Pythagoras rule:

ES² = OE² + OS²

226² = OE² + 161²

226² -  161² = OE²

OE²  =  226² -  161²

OE²  = 51076 - 25921

OE²  =  51076 - 25921

OE²  =  25155

OE = \sqrt{25155}

OE =  158.60 m

OE ≅ 159 m

Thus, the magnitude of the ostrich's towards the eastward component. = 159 m.

4 0
3 years ago
Please help me solve this 200(20)^x&gt;500x+400
s2008m [1.1K]
Hi there!

200(20)^x > 500x + 400

Let's find the critical points of the inequality

200(20^x) = 500x + 400

Now we can divide both sides by 200

(200(20^x))/200 = (500x + 400)/200

20x^x = 5/2 x + 2

There are no critical points.

Thus,

The answer is: No solution

As always, it is my pleasure to help students like you.

6 0
3 years ago
A) x²when x=5<br>b) y²when y=-2<br>c)z²when z=0.5​
Hoochie [10]

Answer:

1.25 \\ 2. - 4 \\ 3.0.25

Step-by-step explanation:

How to find x²

exp. \\  {5}^{2}  = 5 \times 5 = 25 \\  {5}^{3}  = 5 \times 5 \times 5 = 125

8 0
3 years ago
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