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3 years ago

Identify the quadrilateral that has four congruent angles that has two pairs of parallel sides

Mathematics

1 answer:

Anna11 [10]3 years ago

6 0

Answer:

Rhombus

Step-by-step explanation:

Rhombus: A quadrilateral with four congruent sides and two pairs of parallel sides.

<h3>Hope it is helpful...</h3>

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Is 3 tenths x 100 = 30 hundredths

VladimirAG [237]

Answer:

3/10 x 100 = 30.00

Step-by-step explanation:

Three tenths written as a fraction is 3/10. You can also write it as a decimal by simply dividing 3 by 10 which is 0.30.

If you multiply 0.30 with 100 you will see that you will get 30

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3 years ago

✧･ﾟ:Multiple Choice:･ﾟ✧

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Use induction to show that 12 + 22 + 32 + ... + n2 = n(n+1)(2n+1)/6, for all n > 1.

dlinn [17]

Answer with Step-by-step explanation:

Let $P(n)=1^2+2^2+3^2+.....+n^2=\frac{n(n+1)(2n+1)}{6}$

Substitute n=2

Then $P(2)=1+2^2=5$

$P(2)=\frac{2(2+1)(4+1)}{6}=5$

Hence, P(n) is true for n=2

Suppose that P(n) is true for n=k >1

$P(k)=1^2+2^2+3^2+...+k^2=\frac{k(k+1)(2k+1)}{6}$

Now, we shall prove that p(n) is true for n=k+1

$P(k+1)=1^2+2^2+3^2+...+k^2+(k+1)^2=\frac{(k+1)(k+2)(2k+3)}{6}$

LHS

$P(k+1)=1^2+2^2+3^2+.....+k^2+(k+1)^2$

Substitute the value of P(k)

$P(k+)=\frac{k(k+1)(2k+1)}{6}+(k+1)^2$

$P(k+1)=(k+1)(\frac{k(2k+1}{6})+k+1)$

$P(k+1)=(k+1)(\frac{2k^2+k+6k+6}{6})$

$P(k+1)=(k+1)(\frac{2k^2+7k+6}{6})$

$P(k+1)=(k+1)(\frac{2k^2+4k+3k+6}{6})$

$P(k+1)=\frac{(k+1)(k+2)(2k+3)}{6}$

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Hence, P(n) is true for all n >1.

Hence, proved

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3 years ago

Pls answer this , and thank you

irina [24]

——————the answer is 2/25

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A man used 10 gallons of gasoline on a 180-mile trip. How many

Stolb23 [73]

Answer:

Step-by-step explanation:

gs used in 180 mile=10 gallons

gas used in 1 mile=10/180=1/18

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Identify the quadrilateral that has four congruent angles that has two pairs of parallel sides￼￼

Identify the quadrilateral that has four congruent angles that has two pairs of parallel sides