Answer:
The water temperature that produces the maximum number of salmon swimming upstream is approximately 12.305 degrees Celsius.
Step-by-step explanation:
Let
, for
.
represents the temperature of the water, measured in degrees Celsius, and
is the number of salmon swimming upstream to spawn, dimensionless.
We compute the first and second derivatives of the function:
(Eq. 1)
(Eq. 2)
Then we equalize (Eq. 1) to zero and solve for
:

And all roots are found by Quadratic Formula:
, 
Only the first root is inside the given interval of the function. Hence, the correct answer is:

Now we evaluate the second derivative at given result. That is:


According to the Second Derivative Test, a negative value means that critical value leads to a maximum. In consequence, the water temperature that produces the maximum number of salmon swimming upstream is approximately 12.305 degrees Celsius.
Answer:
X=13
Step-by-step explanation:
Isolate the variable by dividing each side by factors that don't contain the variable.
Answer:
The function that can be used in the online shopping club about its monthly revenue is:

Step-by-step explanation:
First, we're gonna take into account the different values we have in the exercise:
- 10,000 members
- $7 per month for membership
- Loses of 400 members by each $1 monthly increase
How the variable
represents the price increase, we can do the formula below:
In this formula, we represent in the first part that by each 1 in the variable
, the total of members will be reduced in 400, in the second part, we mention that at the same time, the membership fee will be increased in the same value of
. Now we must simplify this function:
We operate the values:
Solve we can:
And organize:
At the end, how
represents the monthly revenue received by the club, we use that variable for our formula:
A men's ball is about 9.55 inches<span> (</span>24.26 cm<span>) in diameter and a women's ball is </span>about 9.23 inches<span> (</span>23.44 cm<span>) in diameter.</span>
Answer:
We have 16 ounces of 3% H2O2
How many ounces of 30% H2O2 do we add to make a 10% H2O2 solution?
let x = amount of ounces of 30% H2O2 to add
.03 * 16 + .30x = .10 * (16 + x)
.48 + .30x = 1.6 + .1x
.2x = 1.12
x = 5.6 ounces
Source:
https://www.1728.org/mixture.htm
Step-by-step explanation: