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3 years ago

5

Mark is playing baseball after school. He wants to find the total distance he will need to ride his bike from school to the park

, where his game will be played. Find the distance Mark will ride to the park from school. Leave your answer in
simplest radical form if necessary.

- 6
- square root 13
- 5
- 2 square root 5

2 answers:

Elan Coil [88]3 years ago

8 0

Answer:

i think it's 6.

...........................

Aleonysh [2.5K]3 years ago

6 0

Answer:

2√5

Step-by-step explanation:

school is at (8,7) and park is at (10,11)

distance formula is the square root of the difference of the y-values, squared, added to the difference of the x-values, squared.

d = √(11-7)²+(10-8)²

d = √4²+2²

d = √16+4

d = √20 which equals √4·√5 which equals 2√5

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The distribution of the number of viewers for the American Idol television show follows a normal distribution with a mean of 26

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Answer:

Probability that next week's show will have between 30 and 37 million viewers is 0.2248.

Step-by-step explanation:

We are given that the distribution of the number of viewers for the American Idol television show follows a normal distribution with a mean of 26 million with a standard deviation of 8 million.

<em>Let X = number of viewers for the American Idol television show</em>

So, X ~ N( $\mu=26,\sigma^{2}=8^{2}$ )

Now, the z score probability distribution is given by;

Z = $\frac{X-\mu}{\sigma}$ ~ N(0,1)

where, $\mu$ = population mean = 26 million

$\sigma$ = standard deviation = 8 million

So, probability that next week's show will have between 30 and 37 million viewers is given by = P(30 < X < 37) = P(X < 37) - P(X $\leq$ 30)

P(X < 37) = P( $\frac{X-\mu}{\sigma}$ < $\frac{37-26}{8}$ ) = P(Z < 1.38) = 0.91621

P(X $\leq$ 30) = P( $\frac{X-\mu}{\sigma}$ $\leq$ $\frac{30-26}{8}$ ) = P(Z $\leq$ 0.50) = 0.69146

<em>Therefore, P(30 < X < 37) = 0.91621 - 0.69146 = 0.2248</em>

Hence, probability that next week's show will have between 30 and 37 million viewers is 0.2248.

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3 years ago

Triangle ABC is isosceles with AB=CB. Circle M is inscribed in Triangle ABC such that it is tangent at points D, E, and F. If th

Ierofanga [76]

Answer:

The answer is "12 inches".

Step-by-step explanation:

Please find the image file of the graph.

We know $AE = CF \ and \ EB = FB$ so because the triangle is isosceles.

$EB = 2x, FB = 2x,\ and \ CF = x$ when $AE$ is called by $x$ .

We know that $AE = AD = x$ since E and D are tangent points to a circle.

They have $CD = CF = x$ since D and F are tangent points only to circle.

Thus, if the perimeter is 32, the following is the result:

$\to AE + EB + BF + FC + CD + DA = 32\\\\\to x + 2x + 2x + x + x + x = 32\\\\\to 8x = 32\\\\\to x = 4$

Therefore the length of $BC = BF + FC = 2x + x = 3x = 12\ inches$

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2 years ago

What is the surface area of the right square pyramid shown above ?

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Answer:

answer d is the right answer

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3 years ago

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What is the x-value of point A?

kvv77 [185]

Answer: 5

Step by Step Explanation:

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3 years ago

Rewrite the expression $6j^2 - 4j 12$ in the form $c(j p)^2 q$, where $c$, $p$, and $q$ are constants. What is $\frac{q}{p}$

solniwko [45]

$Rewrite the expression 6j^2 - 4j + 12$ in the form $c(j + p)^2 + q$, where $c$, $p$, and $q$ are constants. What is $\frac{q}{p}$$

The ratio of $\frac{q}{p}$ = - 34

How to solve such questions?

Such Questions can be easily solved just by some Algebraic manipulations and simplifications. We just try to make our expression in the form which question asks us. This is the best method to solve such questions as it will definitely lead us to correct answers. One such method is completing the square method.

Completing the square is a method that is used for converting a quadratic expression of the form $ax^{2} + bx + c$ to the vertex form

$a(x - h)^{2} + k$ . The most common application of completing the square is in solving a quadratic equation. This can be done by rearranging the expression obtained after completing the square: $a(x + m)^{2} + n$ , such that the left side is a perfect square trinomial

$6j^2 - 4j +12$

= $6(j^2 - \frac{2}{3} j )+12$

= $$6(j^2 - \frac{2}{3} j + \frac{1}{9} )+\frac{102}{9}$ (Completing Square method)

= $6( j- \frac{1}{3} )^{2} + \frac{34}{3}$

On comparing with the given equation we get

p = - $\frac{1}{3}$ and q = $\frac{34}{3}$

∴ $\frac{q}{p}$ = $\frac{\frac{34}{3} }{\frac{-1}{3} }$

= - 34

Learn more about completing the square method here :

brainly.com/question/26107616

#SPJ4

7 0

2 years ago