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anastassius [24]
3 years ago
10

A bag contains two red marbles, three blue marbles and four green marbles what is the sample space​

Mathematics
1 answer:
Yuki888 [10]3 years ago
3 0

Answer:

Given in a bag contains five green marbles, three blue marbles, two red marbles and two yellow marbles

(a)The four colour out comes not equally because the number of four colours balls are different.

(b) Total ball =5+3+2+1=11

Then probability (green) =

11

5

Then probability (blue) =

11

3

Then probability (red) =

11

2

Then probability (yellow) =

13

1

(c) The sum of probabiilites =

11

5

+

11

3

+

11

2

+

11

1

=

11

11

=1

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If correct then I’ll mark brainlist
Leto [7]

Answer:

(-11, -12)

Step-by-step explanation:

we need one variable to x out

on the note of x, lets cancel out the xs

6x+3y=-102

3x+y=-45 < same as 6x+2y-90

6x+3y=-102

-

6x+2y=-90

y=-12

substitute y in

3x-12=-45

3x=-33

x=-11

(-11, -12)

Please give brainliest :)

5 0
3 years ago
A circular picture is 8 inches in diameter.
tino4ka555 [31]
For number one I would say c or b for part b I would say it would be b or d but I could be wrong I am sorry if I am
4 0
4 years ago
Find the measure of angle M<br> Only real answers, please<br> See image
astra-53 [7]

Answer:

  • 136°

Step-by-step explanation:

Since the trapezoid is isosceles, the angles J and M are supplementary and angles M and L are congruent, therefore:

  • ∠J + ∠M = 180°
  • ∠J + ∠L = 180°
  • 7x + 2 + 25x - 14 = 180°
  • 32x = 192
  • x = 192/32
  • x = 6

∠M = ∠L = 25*6 - 14° = 150° - 14° = 136°

6 0
3 years ago
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What is the maximum point OR minimun point of this equation?
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Answer is 3 because when you solve its 3 or less
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3 years ago
Suppose we roll one fair six-sided die, and flip six coins. what is the probability that the number of heads is equal to the num
sergejj [24]

The probability that the number of heads is equal to the number showing on the die is \frac{21}{128} .

According to the question

we roll one fair six-sided die, and flip six coins

i.e

The Total Outcomes is the product of the sample spaces for the dice and the coins.  

sample spaces for the dice = 6

sample spaces for the coins = 2⁶

S = 6.2⁶

S = 384

Now, The  probability is

Therefore, the Favorable Outcomes

Consider the number of ways to get each total of heads from 1 to 6.

= 2⁶-1 (as TTT is excluded )

= 63

The probability that the number of heads is equal to the number showing on the die

As

Probability can be defined as the ratio of the number of favorable outcomes to the total number of outcomes of an event.

Probability(Event) = Favorable Outcomes/Total Outcomes

By substituting the values in the formula

Probability(Event) = \frac{63}{384}

Probability(Event) = \frac{21}{128}

Hence, the probability that the number of heads is equal to the number showing on the die is \frac{21}{128}

To know more about probability here:

brainly.com/question/11234923

#SPJ4

3 0
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