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3 years ago

PLEASE HELP WILL GIVE BRAINLIEST!!!

Mathematics

2 answers:

Amanda [17]3 years ago

5 0

Answer:

angle U ( the third option down)

Step-by-step explanation:

Alla [95]3 years ago

3 0

The answer is A hope this helps

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Solve by your method of choice.

34kurt

Answer:

Step-by-step explanation:

Given the 2 equations

x³ + y = 0 → (1)

11x² - y = 0 → (2)

Add (1) and (2) term by term to eliminate the term in y

x³ + 11x² = 0 ← factor out x² from each term

x²(x + 11) = 0

Equate each factor to zero and solve for x

x² = 0 ⇒ x = 0

x + 11 = 0 ⇒ x = - 11

Substitute these values into (1) for corresponding values of y

(1) y = - x³

x = 0 ⇒ y = 0 ⇒ (0, 0) is a solution

x = - 11 ⇒ y = - (- 11)³ = 1331 ⇒ (- 11, 1331) is a solution

6 0

3 years ago

What is the three equivalent fractions for 6/1

Kaylis [27]

12/2, 18/3, 36/6 that is 3 equal fractions. just multiply both parts of the fraction by the same #

8 0

4 years ago

Please Help 50 points!!

REY [17]

Answer:

lol sorry for answer what's that

7 0

3 years ago

If a figure is dilated by a factor of 5/6 ,the perimeter of the figure will change by a factor of

fenix001 [56]

Answer:

1,2,3,6

Step-by-step explanation:

6x1, 2x3, 3x2, 6x1

i study hard and work my hardest

6 0

3 years ago

Read 2 more answers

In the diagram below, R is located at (24,0), N is located at (12,18), T is located at (12,6), and E is located at (18,15). Assu

julsineya [31]

The midpoint of a segment divides the segment into equal halves

The coordinates of K are: $\mathbf{K = (12,12)}$
The coordinates of I are: $\mathbf{I = (24,24)}$
The coordinates of B are: $\mathbf{B = ( 30,33 )}$

The given parameters are:

$\mathbf{R =(24,0)}$

$\mathbf{N =(12,18)}$

$\mathbf{T =(12,6)}$

$\mathbf{E =(18,15)}$

K is the midpoint of N and T.

So, we have:

$\mathbf{K = (\frac{N_x + T_x}{2},\frac{N_y + T_y}{2})}$

This gives

$\mathbf{K = (\frac{12 + 12}{2},\frac{18+ 6}{2})}$

$\mathbf{K = (12,12)}$

E is the midpoint of T and I.

So, we have:

$\mathbf{E = (\frac{I_x + T_x}{2},\frac{I_y + T_y}{2})}$

This gives

$\mathbf{(18,15) = (\frac{I_x + 12}{2},\frac{I_y+ 6}{2})}$

Multiply through by 2

$\mathbf{(36,30) = (I_x + 12,I_y+ 6)}$

By comparison

$\mathbf{I_x + 12 = 36.\ I_y + 6 =30}$

So, we have:

$\mathbf{I_x= 24.\ I_y =24}$

Hence, the coordinates of I are:

$\mathbf{I = (24,24)}$

I is the midpoint of E and B.

So, we have:

$\mathbf{I = (\frac{E_x + B_x}{2},\frac{E_y + B_y}{2})}$

This gives

$\mathbf{(24,24) = (\frac{18 + B_x}{2},\frac{15 + B_y}{2})}$

Multiply through by 2

$\mathbf{(48,48) = (18 + B_x,15 + B_y)}$

By comparison

$\mathbf{18 + B_x = 48,\ 15 + B_y = 48 }$

So, we have:

$\mathbf{B_x = 30,\ B_y = 33 }$

Hence, the coordinates of B are:

$\mathbf{B = ( 30,33 )}$