All categories

3 years ago

Use a factor tree to find the prime factorization of 36

Mathematics

2 answers:

mihalych1998 [28]3 years ago

5 0

6*6 3*3*3*3 are some answers

umka21 [38]3 years ago

3 0

36
6×6
3×3×3×3
that is your answer

You might be interested in

george has 6 cups of tamato sause he needs 3/4 of the sause to make lasagna wich best describes how much sause will George use

Kay [80]

Tomato = 6
lasagna = 3/4tomato
= 4 cups 1/2

4 0

3 years ago

Help me please :).........

VikaD [51]

C I believe it not so sure

5 0

3 years ago

Pls help i need help will give correct brainlyest

Rufina [12.5K]

Answer:

here you go

Step-by-step explanation:

1 is = 2 is >

7 0

3 years ago

PLEASE HELP! The table shows the number of championships won by the baseball and softball leagues of three youth baseball divisi

Irina18 [472]

Answer:

Question 1: $P ( B | Y ) = \frac{ P ( B and Y)}{ P (Y)} = \frac{ \frac{2}{16}}{ \frac{4}{16}} = \frac{1}{2}$

Question 2:

A. $P ( Y | B ) = \frac{ P(Y and B) }{ P(B) } = \frac{ \frac{2}{16} }{ \frac{6}{16} } = \frac{1}{3}$

B. $P( Z | B ) = \frac{ P ( Z and B)}{ P (B)}= \frac{ \frac{1}{16} }{ \frac{6}{16} } = \frac{1}{6}$

C. $P((Y or Z)|B) = \frac{ P ((Y or Z) and B)}{P(B)}= \frac{ \frac{3}{16}}{ \frac{6}{16}}= \frac{1}{2}$

Step-by-step explanation:

Conditional probability is defined by

$P(A|B)= \frac{P(A and B)}{P(B)}$

with P(A and B) beeing the probability of both events occurring simultaneously.

Question 1:

B: Baseball League Championships won, beeing

$P ( B ) = \frac{ 6 }{16}$

Y: Championships won by the 10 - 12 years old, beeing

$P ( Y)= \frac{ 4 }{ 16 }$

then

P( B and Y)= \frac{ 2 }{ 16 }[/tex]

By definition,

$P ( B | Y ) = \frac{ P ( B and Y)}{ P (Y)} = \frac{ \frac{2}{16} }{ \frac{4}{16} } = \frac{1}{2}$

Question 2.A:

Y: Championships won by the 10 - 12 years old, beeing

$P ( Y)= \frac{ 4 }{ 16 }$

B: Baseball League Championships won, beeing

$P ( B ) = \frac{ 6 }{16}$

then

P( B and Y)= \frac{ 2 }{ 16 }[/tex]

By definition,

$P ( Y | B ) = \frac{ P(Y and B) }{ P(B) } = \frac{ \frac{2}{16} }{ \frac{6}{16} } = \frac{1}{3}$

Question 2.B:

Z: Championships won by the 13 - 15 years old, beeing

$P ( Z)= \frac{ 1 }{ 16 }$

B: Baseball League Championships won, beeing

$P ( B ) = \frac{ 6 }{16}$

then

P( Z and B)= \frac{ 1 }{ 16 }[/tex]

By definition,

$P( Z | B ) = \frac{ P ( Z and B)}{ P (B)}= \frac{ \frac{1}{16} }{ \frac{6}{16} } = \frac{1}{6}$

Question 3.B

Y: Championships won by the 10 - 12 years old, beeing

$P ( Y)= \frac{ 4 }{ 16 }$

Z: Championships won by the 13 - 15 years old, beeing

$P ( Z)= \frac{ 1 }{ 16 }$

then

$P (Y or Z) = P(Y) + P(Z) = \frac{6}{16}$

B: Baseball League Championships won, beeing

$P ( B ) = \frac{ 6 }{16}$

$P((YorZ) and B)= \frac{3}{16}$

By definition,

$P((Y or Z)|B) = \frac{ P ((Y or Z) and B)}{P(B)}= \frac{ \frac{3}{16}}{ \frac{6}{16}}= \frac{1}{2}$

3 0

3 years ago

How many ways can you make 65 cents using nickels dimes and quarters

Neporo4naja [7]

Answer:

14 ways in all.

Step-by-step explanation:

A. If you use 2 quarters, you have to make the remaining 15� with either no

dimes or 1 dime and the rest in nickels.

That's 2 ways.

B. If you use 1 quarter, you have to make the remaining 40� with either no

dimes, 1 dime, 2 dimes, 3 dimes or 4 dimes and the rest, if any, in nickels.

That's 5 more ways.

C. If you don't use any quarters, you have to make the entire 65� with either

0, 1, 2, 3, 4, 5 or 6 dimes and the rest in nickels.

That's 7 more ways. 2+5+7 = 14 ways in all.

4 0

3 years ago