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3 years ago

15÷4 as a mixed number

Mathematics

2 answers:

Zielflug [23.3K]3 years ago

8 0

Answer:

3 3/4

Step-by-step explanation:

nevsk [136]3 years ago

5 0

Answer:

15/4 = 3 3/4

Step-by-step explanation:

15/4 = 3 R 3 = 3 3/4

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Don't bought a tree ceiling that was 2 1/4 feet tall during the first year it grew 116 feet after two years it was 5 feet tall h

Llana [10]

The answer is 113.75 or 113 3/4

7 0

3 years ago

The volume of a cylinder is 12,566.4 cm3. The height of the cylinder is 8 cm.

scoundrel [369]

Using the formulas here: http://www.1728.org/diamform.htm

A) Volume = π • r² • height
radius^2 = Volume / (PI*height)
radius^2 = 12,566.4 / (PI * 8)
radius^2 = 500.0011692175 
radius = 22.3607059195 
radius (rounded) = 22.4 cm

B) Area of base = PI * radius^2
Area of base = 3.14159265 * 500
Area of base = 1,570.7963267949 
Area of base (rounded) = 1,570.8 square cm

C) lateral area = 2 • π • r • height 
lateral area = 2 • π • 22.4 * 8
lateral area = 1,125.9468070466 
lateral area = 1,125.9 square cm

D) Total Surface Area = (2 • π • r²) + (2 • π • r • height)
Total Surface Area = 2 * (top AND bottom area which is the Part B answer times 2) + (the lateral area which is the Part C answer)

Total Surface Area = ( 2 * 1,570.8 ) + (1,125.9)
Total Surface Area = 3,141.6 + 1,125.9
Total Surface Area = 4,267.5 square cm

3 0

3 years ago

What is the area of the shaded portion of the circle?

SOVA2 [1]

Answer:

The first option is the correct one, the area of the shaded portion of the circle is

[/tex](5 \pi -11.6)ft^2[/tex]

Step-by-step explanation:

Let us first consider the triangle + the shadow.

The full area of the circle is the radius squared times pi, so

A= $(5 ft)^2 \cdot \pi \\25 ft^2 \cdot \pi$

Since $\frac{72^{\circ}}{360^{\circ}}=\frac{1}{5}$ , the area of the triangle + the shaded area is one fifth of the area of the whole circle, thus

$A_1=\frac{1}{5}25 ft^2 \cdot \pi\\ =5 ft^2 \cdot \pi$

If we want to know the area of the shaded part of the circle, we must subtract the area of the triangle from $A_1$ .

The area of the triangle is given by

$A_{triangle}=\frac{1}{2}\cdot (2.9+2.9)ft \cdot 4 ft\\= 11.6 ft^2$

Thus the area of the shaded portion of the circle is

$A_1-A_{triangle}=5 \pi ft^2-11.6ft^2\\= (5 \pi -11.6)ft^2$

3 0

3 years ago

Integrate the following: ∫<img src="https://tex.z-dn.net/?f=5x%5E4dx" id="TexFormula1" title="5x^4dx" alt="5x^4dx" align="absmid

Fiesta28 [93]

Answer:

A. $x^5+C$

Step-by-step explanation:

This is a great question! The first thing we want to do here is to take the constant out of the expression, in this case 5. Doing so we would receive the following expression -

$5\cdot \int \:x^4dx$