All categories

3 years ago

Please help for points

Mathematics

2 answers:

Arte-miy333 [17]3 years ago

7 0

Step-by-step explanation:

7×2=14(+)

8×2=16=

32squared.

sergejj [24]3 years ago

3 0

Answer:

h=8ft

p=a

b=7ft

now,

h^2=p^2+b^2

8^2=a^2+7^2

64=a^2+49

64-49=a^2

√15=a

You might be interested in

Is the function h(x)= 5 7 –6x+5x2 linear or nonlinear?

Ronch [10]

The function is degree 2 ( because of the x^2) so it is non-linear.

8 0

4 years ago

Sam obtains a $20,000 loan for a new car. If the interest rate is 3.5% with a loan term of 72 months, how much will his monthly

sleet_krkn [62]

Answer: 287.5 monthly payments

Step-by-step explanation:

3.5 = 0.035= 700 20,000 + 700 = 20,700 ÷ 72 =287.5 This is a step by step equation but first you convert or simplify the percent to decimal then you make it to a whole number and you get what the percent is equal to. Next , you add 700 to 20,000 an you get 20,700. Lastly you divided 20,700 by 72 and you get the answer 287.5 .

6 0

3 years ago

The following observations were made on fracture toughness of a base plate of 18% nickel maraging steel (in ksi √in, given in in

Grace [21]

Answer:

A 90% confidence interval for the standard deviation of the fracture toughness distribution is [4.06, 6.82].

Step-by-step explanation:

We are given the following observations that were made on fracture toughness of a base plate of 18% nickel maraging steel below;

68.6, 71.9, 72.6, 73.1, 73.3, 73.5, 75.5, 75.7, 75.8, 76.1, 76.2, 76.2, 77.0, 77.9, 78.1, 79.6, 79.8, 79.9, 80.1, 82.2, 83.7, 93.4.

Firstly, the pivotal quantity for finding the confidence interval for the standard deviation is given by;

P.Q. = $\frac{(n-1) \times s^{2} }{\sigma^{2} }$ ~ $\chi^{2} __n_-_1$

where, s = sample standard deviation = $\sqrt{\frac{\sum (X - \bar X^{2}) }{n-1} }$ = 5.063

$\sigma$ = population standard deviation

n = sample of observations = 22

Here for constructing a 90% confidence interval we have used One-sample chi-square test statistics.

So, 90% confidence interval for the population standard deviation, $\sigma$ is ;

P(11.59 < $\chi^{2}__2_1$ < 32.67) = 0.90 {As the critical value of chi at 21 degrees

of freedom are 11.59 & 32.67}

P(11.59 < $\frac{(n-1) \times s^{2} }{\sigma^{2} }$ < 32.67) = 0.90

P( $\frac{ 11.59}{(n-1) \times s^{2}}$ < $\frac{1}{\sigma^{2} }$ < $\frac{ 32.67}{(n-1) \times s^{2}}$ ) = 0.90

P( $\frac{(n-1) \times s^{2} }{32.67 }$ < $\sigma^{2}$ < $\frac{(n-1) \times s^{2} }{11.59 }$ ) = 0.90

90% confidence interval for $\sigma^{2}$ = [ $\frac{(n-1) \times s^{2} }{32.67 }$ , $\frac{(n-1) \times s^{2} }{11.59 }$ ]

= [ $\frac{21 \times 5.063^{2} }{32.67 }$ , $\frac{21 \times 5.063^{2} }{11.59 }$ ]

= [16.48 , 46.45]

90% confidence interval for $\sigma$ = [ $\sqrt{16.48}$ , $\sqrt{46.45}$ ]

= [4.06 , 6.82]

Therefore, a 90% confidence interval for the standard deviation of the fracture toughness distribution is [4.06, 6.82].

5 0

3 years ago

What is the y-value of the vertex of the function f(x) = –(x + 8)(x – 14)?

MrRissso [65]

The y value of the vertex is 121.

We can find this by first finding the x value of the vertex. The x value of the vertex in a quadratic equation will always be half way between the two zeros. We can find the zeros by setting each parenthesis equal to 0 and solving for x.

Zero #1
(x + 8) = 0 ---> subtract 8 from both sides.
x = -8

Zero #2
(x - 14) = 0 ----> add 14 to both sides.
x = 14

Since we know that the x value of the vertex must be in the middle of these two, we can take the average of them to find it.

(-8 + 14)/2 = 3

So the x value is 3. Now we can plug that into the equation for all of the x's to get the y value.

f(x) = -(x + 8)(x - 14)
f(3) = -(3 + 8)(3 - 14)
f(3) = -(11)(-11)
f(3) = 121

So the y value is 121.

7 0

4 years ago

10) A survey of business students who had taken the Graduate Management Admission Test (GMAT) indicated that students who have s

kupik [55]

Answer:

0.79 ; 0.753

Step-by-step explanation:

Given that:

Students who have spent at least five hours studying GMAT review guides have a probability of 0.85 of scoring above 400 :

≥ 5 hours review = 0.85

Students who do not spend at least five hours reviewing have a probability of 0.65 of scoring above 400

< 5 hours = 0.65

70% (0.7) of business students spend atleast 5 hours review time

A.) probability of scoring above 400

(Proportion who spend atleast 5 hours review time * 0.85) + (Proportion who do not spend atleast 5 hours * 0.65)

Proportion who do not spend atleast 5 hours = (1 - proportion who spend atleast 5 hours) = 1 - 0.7 = 0.3

Hence,

P(scoring above 400) = (0.7 * 0.85) + (0.3 * 0.65) = 0.595 + 0.195

= 0.79

B.) probability that given a student scored above 400, he/she spent at least five hours reviewing for the test.

P(spent ≥5 hours review | score above 400) :

P(spent ≥5 hours review) / P(score > 400)

(0.7 * 0.85) / 0.79

0.595 / 0.79

= 0.753

7 0

3 years ago