Answer:
For a square of side length L, the perimeter is:
P = 4*L
Then if the perimeter of our square is 36 units, we have:
36 units = 4*L
(36 units)/4 = L = 9 units.
Now we know that one vertex of the square is located at (3, 5)
Then another vertex of the square can be at:
A distance of 9 units of this point (such that these vertices are connected by one side of the square)
Some examples can be:
(3 + 9, 5) = (12, 5)
or
(3, 5 + 9) = (3, 14)
These are the simpler options, there are a lot of other possible points that can be another vertes (we can have a circle of radius 9 units centered in the point (3, 5), all these points can be another vertex of the square).
We also can have a vertex that is connected by the diagonal, this point can be:
(3 + 9, 5 + 9) = (12, 14)
or
(3 - 9, 5 - 9) = (-6, -4)
Again, there are a lot of other possible points that can be this vertex (A circle of radius √2*9 units centered in the point (3, 5)).
