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3 years ago

Helaine graphed the equation 12x−4y=3. What was the slope of Helaine’s line?

Mathematics

2 answers:

mr_godi [17]3 years ago

8 0

Answer:

The slope is 3

Step-by-step explanation:

12x−4y=3

Solve for y

Subtract 12x from each side

-12x +12x−4y=-12x+3

-4y = 12x+3

Divide each side by -4

-4y/-4 = -12x / -4 +3/-4

y = 3x -3/4

This is in slope intercept form

y = mx+b where m is the slope and b is the y intercept

The slope is 3

miss Akunina [59]3 years ago

4 0

Answer:

The slope is 3

Step-by-step explanation:

12x−4y=3

Solve for y

Subtract 12x from each side

-12x +12x−4y=-12x+3

-4y = 12x+3

Divide each side by -4

-4y/-4 = -12x / -4 +3/-4

y = 3x -3/4

This is in slope intercept form

y = mx+b where m is the slope and b is the y intercept

The slope is 3

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One - fifth as a percentage?

nikitadnepr [17]

Answer: 0.2

Step-by-step explanation:

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3 years ago

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. Compute the required sample size given the required confidence in the sample results is 99.74% (Z score of 3). The level of al

Shtirlitz [24]

Answer:

900 sample size

Step-by-step explanation:

To determine the sample size for a proportion, the margin of error formula is used to determine this:

$E=Z_{\frac{\alpha}{2} }*\sqrt{\frac{\hat p \hat q}{{n} }$

$n=\hat p \hat q*(\frac{Z_{\frac{\alpha}{2} }}{E} )^2$

Where p is the proportion, E is the margin of error, n is the sample size, q = 1 - p, $Z_\frac{\alpha }{2}$ is the z score.

Since the proportion is not known, the sample size needed to guarantee the confidence interval and error is at p = 0.5 and q = 1 - p = 1 - 0.5 = 0.5

E = 5% = 0.05, $Z_\frac{\alpha }{2}$ = 3. Hence:

$n=0.5*0.5*(\frac{3}{0.05} )^2\\\\n = 900$

6 0

3 years ago

What is the first step in the construction of a line perpendicular to and passing through an external point M? Assume that the c

AVprozaik [17]

Answer:

A.)lPace the compass needle on M and, keeping the compass width the same, draw two arcs that intersect

Step-by-step explanation:

In the construction of a line perpendicular to AB←→ and passing through an external point M the first step must be"Place the compass needle on M and, keeping the compass width the same, draw two arcs that intersect AB←→". After that you can draw arcs from intersection points (keeping the compass width same as before) to the opposite side of M, name it as N than use straightedge to draw line passes through M and n that would be perpendicular line to AB.

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3 years ago

Part A

labwork [276]

An algebraic expression is one that consists of both number(s) and an alphabet(s). The required answers are:

i. Distance from Chenoa's house to the coffee shop = 6.0 miles

ii. Distance from coffee shop to Chenoa's school = 1.5 miles

iii. Distance from Chenoa's house to her school = 7.5 miles

An algebraic expression is one that consists of both number(s) and an alphabet(s). The alphabet is referred to as the unknown whose value has to be determined.

In the given question, let the distance from the coffee shop to Chenoa's school be represented by y.

So that;

The distance from Chenoa's house to the coffee shop = (2y + 3) miles.

The total distance from Chenoa's house to her school = 5y.

This implies that:

(2y + 3) + y = 5y

3y + 3 = 5y

3 = 5y - 3y

2y = 3

y = $\frac{3}{2}$

= 1.5

The distance from the coffee shop to Chenoa's school is 1.5 miles.

Thus;

(2y + 3) = ( 2(1.5) + 3)

= 6

The distance from Chenoa's house to the coffee shop is 6 miles.

And,

5y = 5(1.5)

= 7.5

The total distance from Chenoa's house to her school is 7.5 miles.

For more clarifications on algebraic expressions, visit: brainly.com/question/12792264

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2 years ago

7. If U= {2, 4, 6, 8, 10, 12, 14, 16} and A = {6, 10, 14}, what is A'?

Tresset [83]

The compliment of set A that is A' is equal to {2, 4, 8, 12, 16}.

We are given the universal set as:

U = {2, 4, 6, 8, 10, 12, 14, 16}

We are also given that set A is:

A = {6, 10, 14}

We need to find A'

For this, we will subtract set A from the universal set, U.

So, we get that:

A' = U - A

A' = {2, 4, 6, 8, 10, 12, 14, 16} - {6, 10, 14}

Solving the expression, we get that:

A' = {2, 4, 8, 12, 16}

Therefore, we get that, the compliment of set A that is A' is equal to {2, 4, 8, 12, 16}.

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1 year ago