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cestrela7 [59]
3 years ago
8

DECK is a parallelogram with m∠1 = 20°, m∠(

{2}" align="absmiddle" class="latex-formula">)°, and m∠CED = (9x)°. Find m∠2.

Mathematics
1 answer:
maw [93]3 years ago
7 0

9514 1404 393

Answer:

  m∠2 = 16° or 25°

Step-by-step explanation:

The sum of angles 1 and 2 is congruent to angle CED.

  20° +(x^2)° = (9x)°

  x^2 -9x +20 = 0 . . . . . divide by °, put in standard form

  (x -5)(x -4) = 0 . . . . . . . factor

  x = 5 or 4

  m∠2 = (x^2)° = (5^2)° or (4^2)°

  m∠2 = 16° or 25°

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The probability of something can be expressed as a decimal or as a percent. We know that the probability of something happening
Firdavs [7]

Answer: The probability lies between 0 and 1


Step-by-step explanation:


As from the given information probability of an event lies between 0% to 100% .


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3 0
3 years ago
Please answer the WHOLE question and explain!
exis [7]

The total weight of candies is unknown. Let x = the total weight of candies.

"One student ate 3/20 of all candies and another 1.2 lb":

The first student ate (3/20)x plus 1.2 lb which is 0.15x + 1.2.

"The second student ate 3/5 of the candies and the remaining 0.3 lb."

The second student ate (3/5)x and 0.3 lb which is 0.6x + 0.3.

Altogether the 2 students ate 0.15x + 1.2 + 0.6x + 0.3.

That was all the amount of candies, so that sum equals x.

0.15x + 1.2 + 0.6x + 0.3 = x

Now we solve the equation for x to find what the total amount of candies was.

0.75x + 1.5 = x

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x = 6

The total amount of candies was 6 lb.

The first student ate 0.15x + 1.2 = 0.15(6) + 1.2 = 0.9 + 1.2 = 2.1, or 2.1 lb of candies.

The second student ate 0.6x + 0.3 = 0.6(6) + 0.3 = 3.6 + 0.3 = 3.9, or 3.9 lb of candies.

Answer: The first student ate 2.1 lb of candies, and the second student ate 3.9 lb of candies.

7 0
3 years ago
What is the productof(-3/5)and (-15)
mafiozo [28]

Answer: ok i kown

Step-by-step explanation:

i kown

5 0
3 years ago
Read 2 more answers
Marcellus has a pitcher that contained 5/8 gallon limeade. Marcellus drank 1/4 gallon of the limeade, and Marcy drank 1/8 gallon
mash [69]

Answer:

2/5

Step-by-step explanation:

Given Marcellus drank 1/4 gallon of the limeade and Marcy drank 1/8 gallon of the limeade

Given that only 5/8 portion of the pitcher contains limeade

Total amount drunk = amount drunk by Marcellus + amount drunk by Marcy

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The amount of Limeade remained = The amount initially - the amount drunk

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Fractional part = amount remained / amount initially = \frac{\frac{1}{4} }{\frac{5}{8} } = \frac{2}{5}

8 0
3 years ago
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