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iVinArrow [24]
3 years ago
9

Find the coordinates of the endpoint of the image?

Mathematics
1 answer:
tensa zangetsu [6.8K]3 years ago
3 0

Given:

The end points of the line segment AB are A(-2,-3) and B(4,-1).

The rule of translation is:

(x,y)\to (x+4,y-3)

To find:

The coordinates of the end points of the line segment A'B'.

Solution:

It is given that the end points of the line segment AB are A(-2,-3) and B(4,-1).

We have,

(x,y)\to (x+4,y-3)

By using the above translation rule, we get

A(-2,-3)\to A'(-2+4,-3-3)

A(-2,-3)\to A'(2,-6)

And

B(4,-1)\to B'(4+4,-1-3)

B(4,-1)\to B'(8,-4)

Hence, the endpoint of the line segment A'B' are A'(2,-6) and B'(8,-4).

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Please help!!!!! Nowwww
never [62]

Answer:

It has 1 term and a degree of 4.

Step-by-step explanation:

3j⁴k-2jk³+jk³-2j⁴k+jk³

= 3j⁴k-2j⁴k-2jk³+jk³+jk³

= j⁴k

So, in this expression, there is 1 term, and it has a degree of 4.

8 0
3 years ago
Add using scientific notation.<br> (5.2 x 10') + (3.01 x 10^)
satela [25.4K]

Answer: What's the exponents?

Step-by-step explanation:

5.2+3.01=8.21

but then there's no exponents that you stated. So it would be 8.21x10^?

If the tens do have exponents above them, add them together.

I hope this answer helps you!

7 0
4 years ago
If x varies directly as y, and x = 7.5 when y = 10, find x when y = 4
Ivanshal [37]

\bf \qquad \qquad \textit{direct proportional variation} \\\\ \textit{\underline{y} varies directly with \underline{x}}\qquad \qquad y=kx\impliedby \begin{array}{llll} k=constant\ of\\ \qquad variation \end{array} \\\\[-0.35em] \rule{34em}{0.25pt}

\bf \stackrel{\textit{"x" varies with "y"}}{x=ky}\qquad \textit{we also know that } \begin{cases} x=7.5\\ y=10 \end{cases}\implies 7.5=k(10) \\\\\\ \cfrac{7.5}{10}\implies \cfrac{~~\frac{15}{2}~~}{10}=k\implies \cfrac{3}{4}=k~\hfill \boxed{x=\cfrac{3}{4}y} \\\\\\ \textit{when y = 4, what is \underline{x}?}\qquad x=\cfrac{3}{~~\begin{matrix} 4 \\[-0.7em]\cline{1-1}\\[-5pt]\end{matrix}~~}(~~\begin{matrix} 4 \\[-0.7em]\cline{1-1}\\[-5pt]\end{matrix}~~)\implies x=3

8 0
3 years ago
PLEASE HELP ME!!! VDUE AT 9 O'CLOCK !!!!!
aleksklad [387]
I believe the answer is B. I graphed it and there was only one intersecting point
4 0
3 years ago
Find the distance CD rounded to the nearest tenth<br> C=(10,-1) and D=(-6,3)
Fynjy0 [20]

Answer:

CD = 16.5

Step-by-step explanation:

To find the distance between two points, use this formula: L = \sqrt{(x_{2} -x_{1})^{2}+(y_{2} -y_{1})^{2} }

point C can be info set 1: (10, -1)    x₁ = 10   y₁ = -1

point D can be info set 2: (-6, 3)    x₂ = -6  y₂ = 3

Substitute the information into the formula

L = \sqrt{(x_{2} -x_{1})^{2}+(y_{2} -y_{1})^{2} }

CD = \sqrt{(-6 -10)^{2}+(3 -(-1))^{2} }    Simplify inside each bracket

CD = \sqrt{(-16)^{2}+(4)^{2} }    Square the numbers

CD = \sqrt{256+16 }     Add inside the root

CD = \sqrt{272}    Enter into calculator

CD = 16.5  Rounded to the nearest tenth, the first decimal

The distance CD is 16.5.

4 0
4 years ago
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