Ask question

Ask question

All categories

4 years ago

8

How much will the ball hold?

1 answer:

kvasek [131]4 years ago

6 0

3280.5 inches cubed is the answer

You might be interested in

What is that answer to that math problem ?

vazorg [7]

Answer:

1. x = 20

2. x = 5.25

3. x = 35

Step-by-step explanation:

Hope this helps!

6 0

3 years ago

2. "Eight more than the quotient of a number<br> and -5 is less than or equal to 6."

Olenka [21]

Answer: $8 + \frac x{-5} \leq 6$

Step-by-step explanation:

Just translate it word-for-word.

"Eight" : 8

"more than" : +

"quotient of" : /

"a number" : x

"-5" : -5

"is less than or equal to" : $\leq$

"6" : 6

6 0

2 years ago

Write this number in standard form 70,000 + 5,000 + 20+3

serg [7]

Answer:

70,523

Step-by-step explanation:

This is standard form there no way to show.

6 0

3 years ago

Which of the following would produce a cross section that is the shape of a triangle?

stellarik [79]

It’s A o did that already

3 0

3 years ago

Will crown the correct answers brainliest 3x

Solnce55 [7]

Answer :

(1) $\frac{1}{x}+\frac{1}{y}=\frac{y+x}{xy}$

(2) $\frac{1}{5x}+\frac{1}{3y}=\frac{3y+5x}{15xy}$

(3) $\frac{1}{7x}-\frac{1}{2y}=\frac{2y-7x}{14xy}$

(4) $\frac{2}{5x}+\frac{3}{7y}=\frac{6y+15x}{21xy}$

(5) $\frac{7}{11x}-\frac{1}{33y}=\frac{231y-11x}{363xy}$

(6) $\frac{1}{2x}+\frac{3}{x}-\frac{1}{7y}=\frac{7y+42y-2x}{14xy}$

Step-by-step explanation :

(1) The given expression is: $\frac{1}{x}+\frac{1}{y}$

$\frac{1}{x}+\frac{1}{y}=\frac{y+x}{xy}$

(2) The given expression is: $\frac{1}{5x}+\frac{1}{3y}$

$\frac{1}{5x}+\frac{1}{3y}=\frac{3y+5x}{(5x)\times (3y)}=\frac{3y+5x}{15xy}$

(3) The given expression is: $\frac{1}{7x}-\frac{1}{2y}$

$\frac{1}{7x}-\frac{1}{2y}=\frac{2y-7x}{(7x)\times (2y)}=\frac{2y-7x}{14xy}$

(4) The given expression is: $\frac{2}{5x}+\frac{3}{7y}$

$\frac{2}{5x}+\frac{3}{7y}=\frac{(2\times 3y)+(3\times 5x)}{(5x)\times (7y)}=\frac{6y+15x}{21xy}$

(5) The given expression is: $\frac{7}{11x}-\frac{1}{33y}$

$\frac{7}{11x}-\frac{1}{33y}=\frac{(7\times 33y)-(1\times 11x)}{(11x)\times (33y)}=\frac{231y-11x}{363xy}$

(6) The given expression is: $\frac{1}{2x}+\frac{3}{x}-\frac{1}{7y}$

$\frac{1}{2x}+\frac{3}{x}-\frac{1}{7y}=\frac{(x\times 7y)+(3\times 2x\times 7y)-(2x\times x)}{(2x)\times (x)\times (7y)}=\frac{7xy+42xy-2x^2}{14x^2y}=\frac{7y+42y-2x}{14xy}$

7 0

3 years ago