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Inessa05 [86]
3 years ago
14

A number y multiplied by —3 is less than

Mathematics
1 answer:
Aliun [14]3 years ago
5 0

Answer:

-3y < -2/5

Step-by-step explanation:

Multiplied means times

-3y

is less than means <

-3y < -2/5

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The diagram shows the straight line which passes through the points (0, 1) and (3, 13).
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Answer:

y=4x+1

Step-by-step explanation:

First find the gradient of the straight line

Then substitute the gradient in the formula y=mx+c.

Substitute one of the given coordinates in the line to find the value of c.

After finding the value of c substitute it in the formula but do not write the values of x and y in the formula

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3 years ago
An item costs $300 before tax, and the sales tax is $9.90 . Find the sales tax rate. Write your answer as a percentage.
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Step-by-step explanation:

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8 0
2 years ago
Which expression is equivalent
Tatiana [17]

Given expression is

\sqrt[4]{\frac{16x^{11}y^8}{81x^7y^6}}

Radical is fourth root

first we simplify the terms inside the radical

\frac{x^{11}}{x^7}=x^4

\frac{y^(8)}{y^6}=y^2

So the expression becomes

\sqrt[4]{\frac{16x^4y^2}{81}}

Now we take fourth root

\sqrt[4]{16} = 2

\sqrt[4]{81} = 3

\sqrt[4]{x^4} = x

We cannot simplify fourth root (y^2)

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\frac{2x\sqrt[4]{y^2}}{3}

Answer is option B


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3 years ago
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Um it is the third brainiest please
4 0
3 years ago
Read 2 more answers
an inverted conical water tank with a height of 20 ft and a radius of 8 ft is drained through a hole in the vertex (bottom) at a
viktelen [127]

Answer:

the rate of change of the water depth when the water depth is 10 ft is;  \mathbf{\dfrac{dh}{dt}  = \dfrac{-25}{100  \pi} \  \ ft/s}

Step-by-step explanation:

Given that:

the inverted conical water tank with a height of 20 ft and a radius of 8 ft  is drained through a hole in the vertex (bottom) at a rate of 4 ft^3/sec.

We are meant to find the  rate of change of the water depth when the water depth is 10 ft.

The diagrammatic expression below clearly interprets the question.

From the image below, assuming h = the depth of the tank at  a time t and r = radius of the cone shaped at a time t

Then the similar triangles  ΔOCD and ΔOAB is as follows:

\dfrac{h}{r}= \dfrac{20}{8}    ( similar triangle property)

\dfrac{h}{r}= \dfrac{5}{2}

\dfrac{h}{r}= 2.5

h = 2.5r

r = \dfrac{h}{2.5}

The volume of the water in the tank is represented by the equation:

V = \dfrac{1}{3} \pi r^2 h

V = \dfrac{1}{3} \pi (\dfrac{h^2}{6.25}) h

V = \dfrac{1}{18.75} \pi \ h^3

The rate of change of the water depth  is :

\dfrac{dv}{dt}= \dfrac{\pi r^2}{6.25}\  \dfrac{dh}{dt}

Since the water is drained  through a hole in the vertex (bottom) at a rate of 4 ft^3/sec

Then,

\dfrac{dv}{dt}= - 4  \ ft^3/sec

Therefore,

-4 = \dfrac{\pi r^2}{6.25}\  \dfrac{dh}{dt}

the rate of change of the water at depth h = 10 ft is:

-4 = \dfrac{ 100 \ \pi }{6.25}\  \dfrac{dh}{dt}

100 \pi \dfrac{dh}{dt}  = -4 \times 6.25

100  \pi \dfrac{dh}{dt}  = -25

\dfrac{dh}{dt}  = \dfrac{-25}{100  \pi}

Thus, the rate of change of the water depth when the water depth is 10 ft is;  \mathtt{\dfrac{dh}{dt}  = \dfrac{-25}{100  \pi} \  \ ft/s}

4 0
4 years ago
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