Answer:
the average of this new list of numbers is 94
Step-by-step explanation:
Hello!
To answer this question we will assign a letter to each number for the first list and the second list of numbers, remembering that the last number of the first list is 80 and the last number of the second list is 96
for the first list
for the new list
To solve this problem consider the following
1.X is the average value of the second list
2. We will assign a Y value to the sum of the numbers a, b, c.
a + b + c = Y to create two new equations
for the first list
solving for Y
Y=(90)(4)-80=280
Y=280=a+b+c
for the second list
the average of this new list of numbers is 94
Answer:
2
Step-by-step explanation:
m= (y-y1)/(x-x1)
Points are (3, -2) and (6, 4)
m= (-2-4)/(3-6)= -6/-3= 2
m=2 to replace ? mark
ANSWER : (9u - 8)2
STEPS:
Step-1 : Multiply the coefficient of the first term by the constant 81 • 64 = 5184
Step-2 : Find two factors of 5184 whose sum equals the coefficient of the middle term, which is -144 .
Step-3 : Rewrite the polynomial splitting the middle term using the two factors found in step 2 above, -72 and -72
81u2 - 72u - 72u - 64
Step-4 : Add up the first 2 terms, pulling out like factors :
9u • (9u-8)
Step-5 : Add up the four terms of step 4 :
(9u-8) • (9u-8)
Which is the desired factorization
88.21 fram is the anserer
So if you have 192 marbles and you want to group them in groups of 15 marbles each
you would see how many times 15's there are in 192 or how many 192's would go into 15
so 192/15 or
12 and 12/15
