All categories

3 years ago

Define these sets by listing their elements:

Mathematics

1 answer:

Vika [28.1K]3 years ago

4 0

Answer:

{13,23,33,43,53,63,73,83,93}

Step-by-step explanation:

These are the conditions given for the set.

The members of the set must 2-digit numbers, therefore it means they are in between 10 and 99.
The numbers are odd. Odd numbers are numbers that <u>cannot be divided exactly by 2.</u>
The numbers must have 3 in them.

So our goal is to get the set of all odd numbers between 10 and 99 that have 3 in them.

The elements of the set are:

{13,23,33,43,53,63,73,83,93}

You might be interested in

Assume Y=1+X+u, where X, Y, and u=v+X are random variables, v is independent of X; E(v)=0, Var(v)=1, E(X)=1, and

kobusy [5.1K]

Answer:

a) $E(u|X=1)= E(v|X=1) + E(X|X=1) = E(v) +1 = 0 +1 =1+$

b) $E(Y| X=1)= E(1|X=1) + E(X|X=1) + E(u|X=1) = E(1) + 1 + E(v) + 0 = 1+1+0=2$

c) $E(u|X=2)= E(v|X=2) + E(X|X=2) = E(v) +2 = 0 +2 =2$

d) $E(Y| X=2)= E(1|X=2) + E(X|X=2) + E(u|X=2) = E(2) + 2 + E(v) + 2 = 2+2+2=6$

e) $E(u|X) = E(v+X |X) = E(v|X) +E(X|X) = E(v) +E(X) = 0+1=1$

f) $E(Y|X) = E(1+X+u |X) = E(1|X) +E(X|X) + E(u|X) = 1+1+1=3$

g) $E(u) = E(v) +E(X) = 0+1=1$

h) E(Y) = E(1+X+u) = E(1) + E(X) +E(v+X) = 1+1 + E(v) +E(X) = 1+1+0+1 = 3[/tex]

Step-by-step explanation:

For this case we know this:

$Y = 1+X +u$

$u = v+X$

with both Y and u random variables, we also know that:

$[tex] E(v) = 0, Var(v) =1, E(X) = 1, Var(X)=2$

And we want to calculate this:

Part a

$E(u|X=1)= E(v+X|X=1)$

Using properties for the conditional expected value we have this:

$E(u|X=1)= E(v|X=1) + E(X|X=1) = E(v) +1 = 0 +1 =1$

Because we assume that v and X are independent

Part b

$E(Y| X=1) = E(1+X+u|X=1)$

If we distribute the expected value we got:

$E(Y| X=1)= E(1|X=1) + E(X|X=1) + E(u|X=1) = E(1) + 1 + E(v) + 0 = 1+1+0=2$

Part c

$E(u|X=2)= E(v+X|X=2)$

Using properties for the conditional expected value we have this:

$E(u|X=2)= E(v|X=2) + E(X|X=2) = E(v) +2 = 0 +2 =2$

Because we assume that v and X are independent

Part d

$E(Y| X=2) = E(1+X+u|X=2)$

If we distribute the expected value we got:

$E(Y| X=2)= E(1|X=2) + E(X|X=2) + E(u|X=2) = E(2) + 2 + E(v) + 2 = 2+2+2=6$

Part e

$E(u|X) = E(v+X |X) = E(v|X) +E(X|X) = E(v) +E(X) = 0+1=1$

Part f

$E(Y|X) = E(1+X+u |X) = E(1|X) +E(X|X) + E(u|X) = 1+1+1=3$

Part g

$E(u) = E(v) +E(X) = 0+1=1$

Part h

E(Y) = E(1+X+u) = E(1) + E(X) +E(v+X) = 1+1 + E(v) +E(X) = 1+1+0+1 = 3[/tex]

8 0

3 years ago

Can someone help me solve this?

svlad2 [7]

Answer:

The axis of symetary would be -1.

6 0

3 years ago

The average low temperature in a city in August is 49 degrees Fahrenheit and the average high temperatures is 71 degrees fahrenh

Darya [45]

Low August: 9 C or 9.4 C if you need specifics

Avg. August: 22 C or 21.66 if you need specifics

6 0

3 years ago

Read 2 more answers

Write the equivalent fraction, the reduced fraction, and the decimal equivalent for 45%. Jenny solved this problem and her work

Nadya [2.5K]

Answer:

Equivalent fraction: 45/100

Reduced fraction: 9/20

Decimal equivalent: 0.45

Step-by-step explanation:

Equivalent fraction: percentage is just out of 100. 45% is 45 out of 100, aka 45/100.

Reduced fraction is just simplifying both sides by the GCF. In this case, 5.

Decimal equivalent of a percentage is just dividing the numerator by the denominator, or taking the numerator or the percentage and placing the decimal point forward two digits.

6 0

3 years ago

Read 2 more answers

Determine if the function is linear or nonlinear

love history [14]

Answer:

llinear

Step-by-step explanation:

8 0

3 years ago