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Neko [114]
2 years ago
8

B = Round your answer to the nearest hundredth. А 4 C B 3

Mathematics
1 answer:
rusak2 [61]2 years ago
6 0

Answer:

(C)

Step-by-step explanation:

Bec this is the best way to get

the answer really like I have a lot to do with me and

o get out and you h gf dfgjj ygdf

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Click an item in the list or group of pictures at the bottom of the problem and, holding the button down, drag it into the corre
Ne4ueva [31]
Slope of AD = (2k - 0)/(2j -b - 0) = 2k/(2j - b)
slope of BC = (2k - 0)/(2j - b) = 2k / (2j - b)
AD ║ BC (same slope)

Slope of AB = 0
Slope of DC = 0

AB║DC

7 0
3 years ago
Read 2 more answers
Can someone help me its urgent:( ??
wariber [46]

Answer:

see the procedure

Step-by-step explanation:

Identify

Let

x ---> the cost of the Xbox one at Walmart

Strategy

we know that

The cost of the Xbox one at Walmart multiplied by 2 plus $50 must be equal to $450

Set up

The algebraic expression that represent this situation is

450=2x+50

Solve

solve for x

450=2x+50

2x=450-50\\2x=400\\x=\$200

Check

substitute the value of x in the equation

450=2(200)+50

450=450 ----> is ok

6 0
3 years ago
Compare the weather on two different days using an inequality. Then see if their comparisons change by finding the absolute valu
dusya [7]

Inequalities are used to compare unequal expressions.

The actual comparison is:\mathbf{-3.5 < 5} or \mathbf{5 > -3.5}

The temperatures are given as:

\mathbf{Temperature =  -3.5F,\ \  5F,\ \  1.5F,\ \  -0.5F,\ \ -2F,\  \ 2.5F,\ \  -4F}

From the above list, we have:

\mathbf{Day \ 1=  -3.5F}

\mathbf{Day \ 2=  5F}

By comparison,

\mathbf{-3.5 < 5} or \mathbf{5 > -3.5}

Using absolute values, the inequalities are:

\mathbf{|-3.5| < |5|} or \mathbf{|5| > |-3.5|}

Hence, the actual comparison is:

\mathbf{-3.5 < 5} or \mathbf{5 > -3.5}

Read more about inequalities and absolute values at:

brainly.com/question/24797699

7 0
3 years ago
Read 2 more answers
Discuss the validity of the following statement. If the statement is always​ true, explain why. If​ not, give a counterexample.
Zarrin [17]

Correction:

Because F is not present in the statement, instead of working on​P(E)P(F) = P(E∩F), I worked on

P(E∩E') = P(E)P(E').

Answer:

The case is not always true.

Step-by-step explanation:

Given that the odds for E equals the odds against E', then it is correct to say that the E and E' do not intersect.

And for any two mutually exclusive events, E and E',

P(E∩E') = 0

Suppose P(E) is not equal to zero, and P(E') is not equal to zero, then

P(E)P(E') cannot be equal to zero.

So

P(E)P(E') ≠ 0

This makes P(E∩E') different from P(E)P(E')

Therefore,

P(E∩E') ≠ P(E)P(E') in this case.

8 0
3 years ago
HOW CAN ARITHMETIC AND GEOMETRIC SEQUENCES BECOME LINEAR AND EXPONENTIAL FUNCTIONS?
vladimir1956 [14]
A sequence is a set of numbers, called terms, arranged in some particular order. An arithmetic sequence is a sequence with the difference between two consecutive terms constant. The difference is called the common difference. A geometric sequence is a sequence with the ratio between two consecutive terms constant.
3 0
3 years ago
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