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3 years ago

Describe in your own words "closed operations.

Mathematics

2 answers:

Deffense [45]3 years ago

7 0

Closed operations is like closing the doors or ending a certain operation that was once ongoing.

const2013 [10]3 years ago

6 0

Answer:

Closed means to closed the doors

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James has to fill 40 water bottles for the soccer team. Each bottle holds 500 milliliters of water. How many liters of water doe

Mandarinka [93]

Answer:

Step-by-step explanation:

5 0

3 years ago

Read 2 more answers

Find the solution of the given initial value problem:<br><br> y''- y = 0, y(0) = 2, y'(0) = -1/2

igor_vitrenko [27]

Answer: The required solution of the given IVP is

$y(x)=\dfrac{3}{4}e^x+\dfrac{5}{4}e^{-x}.$

Step-by-step explanation: We are given to find the solution of the following initial value problem :

$y^{\prime\prime}-y=0,~~~y(0)=2,~~y^\prime(0)=-\dfrac{1}{2}.$

Let $y=e^{mx}$ be an auxiliary solution of the given differential equation.

Then, we have

$y^\prime=me^{mx},~~~~~y^{\prime\prime}=m^2e^{mx}.$

Substituting these values in the given differential equation, we have

$m^2e^{mx}-e^{mx}=0\\\\\Rightarrow (m^2-1)e^{mx}=0\\\\\Rightarrow m^2-1=0~~~~~~~~~~~~~~~~~~~~~~~~~~[\textup{since }e^{mx}\neq0]\\\\\Rightarrow m^2=1\\\\\Rightarrow m=\pm1.$

So, the general solution of the given equation is

$y(x)=Ae^x+Be^{-x},$ where A and B are constants.

This gives, after differentiating with respect to x that

$y^\prime(x)=Ae^x-Be^{-x}.$

The given conditions implies that

$y(0)=2\\\\\Rightarrow A+B=2~~~~~~~~~~~~~~~~~~~~~~~~~~~(i)$

and

$y^\prime(0)=-\dfrac{1}{2}\\\\\\\Rightarrow A-B=-\dfrac{1}{2}~~~~~~~~~~~~~~~~~~~~~~~~(ii)$

Adding equations (i) and (ii), we get

$2A=2-\dfrac{1}{2}\\\\\\\Rightarrow 2A=\dfrac{3}{2}\\\\\\\Rightarrow A=\dfrac{3}{4}.$

From equation (i), we get

$\dfrac{3}{4}+B=2\\\\\\\Rightarrow B=2-\dfrac{3}{4}\\\\\\\Rightarrow B=\dfrac{5}{4}.$

Substituting the values of A and B in the general solution, we get

$y(x)=\dfrac{3}{4}e^x+\dfrac{5}{4}e^{-x}.$

Thus, the required solution of the given IVP is

$y(x)=\dfrac{3}{4}e^x+\dfrac{5}{4}e^{-x}.$

4 0

3 years ago

Do i need to flip the reciprocal please explain your answer<br> 2y/2 < 10/2

saul85 [17]

Answer:

$\displaystyle \large \boxed{y < 5}$

Step-by-step explanation:

We are given the Inequality:

$\displaystyle \large{ \frac{2y}{2} < \frac{10}{2} }$

First, we can simplify the expression. On the left side of Inequality, we can cancel 2; on the right side, we can cancel 2 out as well.

Simply, division!

$\displaystyle \large{ \frac{ \cancel{2}y}{ \cancel{2}} < \frac{ \cancel{10}}{ \cancel{2} }}$

2 divides 2 is 1; 2 divides 10 is 5.

$\displaystyle \large{ \frac{1y}{1} < \frac{ 5}{ 1}}$

Generally, it is not recommended to write 1 beside the variable nor write 1 as a denominator.

Simplify the expression:-

$\displaystyle \large{ y < 5}$

Therefore, the value of y is less than 5.

Let me know if you have any questions after reading the explanation!

7 0

2 years ago

armand deposited $389.42 in a savings account that earns 3.2% simple interest. what is armand’s account balance after 7 years?

butalik [34]

Okay so since we have $389.42 to start with, we will multiply that by 3.2% which gives us roughly $12.46. Knowing that he will get an additional $12.46 per year, we multiply 12.46 by 7, giving us $87.22. Now, we just add 87.22 to 389.42, which is 476.64. Therefore, Armand has $476.64 as his account after 7 years.

7 0

3 years ago

5. a : 4, for a = 32

Dmitrij [34]

Answer:

Step-by-step explanation:

put 4 in place for a

4=32

dive both sides by 4 and you will get 8

hope this helps

8 0

3 years ago