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Arturiano [62]
2 years ago
6

A committee must be formed with 4 teachers and 5 students. If there are 7 teachers to choose from, and 15 students, how many dif

ferent ways could the committee be made?
Mathematics
2 answers:
nikitadnepr [17]2 years ago
6 0

Answer:

Step-by-step explanation:

There are a total of 10 persons (6 teachers + 4 students) from which a committee of 5 is to be formed. This can be done in 10C5 ways.

The number of ways that a committee can be formed with no students in it is to select 5 teachers out of the pool of 6 teachers available. This can be done in 6C5 ways.

Therefore the total number of ways that the committee can be formed with at least one student in it is 10C5 - 6C5.

10C5 = 252

6C5 = 6

Therefore the required number of ways = 246

sleet_krkn [62]2 years ago
5 0
Mulitply

C(6,4)*C(12,4)

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National statistics show that 23% of men smoke and 18.5% of women smoke. A random sample of 175 men indicated that 45 were smoke
NeTakaya

Answer:

98% C.I. = [-0.1270, 0.0994]

Step-by-step explanation:

Here

p1= proportion of men smokers

p1= 45/175= 0.2571

p2= proportion of women smokers

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1)  Choose the significance level ∝= 0.02

2) The formula for confidence interval is

(p1^- p2^)- z ∝/2sqrt( p1^(1-p1^)/n1 + ( p2^(1-p2^)/n2))

and

(p1^- p2^) z ∝/2sqrt( p1^(1-p1^)/n1 + ( p2^(1-p2^)/n2))

<u>3)  The z value is 2.05</u>

<u>4) Calculations:</u>

(p1^- p2^)- z ∝/2sqrt( p1^(1-p1^)/n1 + ( p2^(1-p2^)/n2))

Putting the values

= 0.2571-0.2709)(-2.05) sqrt ( 0.2571(1-0.2571)/175+ 0.2709(1-0.2709)/155)

=-0.1270 ( using calculator)

And

(p1^- p2^)z ∝/2sqrt( p1^(1-p1^)/n1 + ( p2^(1-p2^)/n2))

Putting the values

= 0.2571-0.2709)(2.05) sqrt ( 0.2571(1-0.2571)/175+ 0.2709(1-0.2709)/155)

=0.0994  ( using calculator)

and Putting ± 2.05 in the confidence interval formula we get limits (-0.1270, 0.0994)

6 0
3 years ago
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Step 2: Add 2 to both sides.

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Step 3: Divide both sides by -2.

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