Ask question

Ask question

All categories

3 years ago

5

I need help please! In each case below, list the lettered measures for angles or sides in descending order (FROM GREATEST TO LEA

ST).

1 answer:

Hitman42 [59]3 years ago

8 0

Answer:

a > b > c

Step-by-step explanation:

The longest side is the one that sees the angle with the biggest measure

The angles are shown in the image, the third angle is 75 degrees (because the sum of interior angle is equal to 180)

So the list of the sides in descending order is as follows :

a > b > c (a sees angle measure 75, b sees angle measure 70, and c sees angle measure 35)

You might be interested in

Values of k for which the quadratic equation 2x - kx + k 0 has equal roots is

WARRIOR [948]

Answer:

The answer is D.

Step-by-step explanation:

We have to apply Discriminant Law. When a quadratic equation, ax² + bx + c = 0 has equal roots so the discriminant will be 0. Then, you have to substitute the values into the formula :

$D = {b}^{2} - 4ac$

$let \: D = 0 ,a = 2,b = k,c = k$

$0 = {k}^{2} - 4(2)(k)$

${k}^{2} - 8k = 0$

$k(k - 8) = 0$

$k = 0$

$k - 8 = 0$

$k = 8$

4 0

4 years ago

NEED ANSWER ASAP!!!

irga5000 [103]

Answer:

c) 10 feet

Step-by-step explanation:

Pythagorean theorum! Wonderful! (remember that c is the hypotenuse)

a^2 + b^2 = c^2

8^2 + 6^2 = c^2

64 + 36 = c^2

100 = c^2

square root of 100 = c^2

10 = c^2

6 0

3 years ago

Solve for x, given the equation Square root of x plus 9 − 4 = 1.

Daniel [21]

ANSWER

The value of x is
$16.$

EXPLANATION

We want to solve the equation,

$\sqrt{x + 9} - 4 = 1$

The first step is to add 4 to both sides of the equation to obtain,

$\sqrt{x + 9} = 1 + 4$

We simplify the right hand side to obtain,

$\sqrt{x + 9} = 5$

We now square both sides of the equation to obtain,

$(\sqrt{x + 9} ) ^{2} = {5}^{2}$

This simplifies to

$x + 9= 25$

We solve for x to obtain,

$x = 25 - 9$

This implies that,

$x = 16$

4 0

3 years ago

Let g(x, y) = cos(x + 5y). (a) Evaluate g(10, −2). g(10, −2) = (b) Find the domain of g. −1 ≤ x ≤ 1, − 1 5 ≤ y ≤ 1 5 −5 ≤ x ≤ 5,

RoseWind [281]

Answer:

since $Cos(z)$ is a function defined for all $z\in \mathbb{R}$ , then there is not restriction for $x+5y$ , thus, the domain of $g(x,y)$ is $\mathbb{R}^2$ and in interval notation is $(-\infty,\infty)\times(-\infty,\infty)$

Since $Cos(x+5y)\in\mathbb{R}$ then the range of $g(x,y)$ is the interval [-1,1].

4 0

4 years ago

PLEASE HELP FOR BRAINLIEST ANSWER!!! AND A HUGE THANKYOU

MrRa [10]

It is reflecting across the x-axis

3 0

3 years ago

Read 2 more answers