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2 years ago

Problem situation:

Mathematics

2 answers:

stepladder [879]2 years ago

7 0

Answer:

Rewrite so x is on the left side of the inequality.

8 + 4.99x < 20

Move all terms not containing x to the right side of the inequality.

4.99x < 12

Divide each term by 4.99 and simplify.

x < 2.405

The result can be shown in multiple forms.

Inequality Form:

x < 2.405

Interval Notation:

( −∞ , 2.405 )

Step-by-step explanation:

yulyashka [42]2 years ago

5 0

Answer:

Both:

Inequality Only:

-4

3/4

2.3

Neither:

2.5

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Step-by-step explanation:

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3 years ago

Read 2 more answers

Given: ∠AOC, ∠BOC - complementary angles

34kurt

Answer:

30
COB . . . . or . . . . BOC

Step-by-step explanation:

The reason given on the line of interest is "substitution," so the problem boils down to determining what was substituted for what. The previous statement says ...

AOC + COB = 90

and the first part of the statement we're to complete has BOC + ___.

We see from the given statements that m∠AOC = m∠BOC + 30°, so it appears that is the substitution that has been made: AOC has been replaced by BOC + 30.

This means the first blank is filled with 30.

The second part of the previous statement is ...

AOC + COB = 90

so we believe this (COB) should go in the second blank.

Then the line of interest would read ...

BOC + 30 + COB = 90

_____

Comment on the problem

There is a curious mix of notations here. Usually, (as in the beginning of this problem) we refer to the measure of an angle using "m∠" in front of the angle designator, and we use a degree symbol to indicate the units of that measure. Part-way through the problem statement written here, those notations were dropped, and we're to assume they are intended. IMO, this is a poor way to demonstrate careful problem solving.

The substitution given for AOC is BOC+30, but the line into which that is substituted has AOC +COB = 90. This means the equation after substitution is ...

BOC +30 +COB = 90

Since BOC and COB are the same angle, we can sort of fudge the "algebra" to get to BOC=30, but if the problem were more carefully written, the angle would be referred to by consistent nomenclature:

m∠AOC + m∠BOC = 90° . . . . . . . . . preferred angle designations

(m∠BOC + 30°) + m∠BOC = 90° . . . . substitution for m∠AOC

2(m∠BOC) = 60° . . . . . . algebra (subtract 30°, collect terms)

m∠BOC = 30° . . . . . . . . algebra (divide by 2)

3 0

3 years ago

Please solve this question!!

GaryK [48]

Answer: (i) 1/221 (ii) 11/221 (iii) 95/663 (iv) 1/663

Step-by-step explanation:

(i) A deck of cards contains 4 Kings out of 52 total cards

1st draw: 4 Kings out of 52 total cards → 4/52 = 1/13

2nd draw: 3 remaining Kings out of 51 total remaining cards → 3/51 = 1/17

1st Draw 2nd Draw Outcome Probability

King: P(K) = 1/13 King: P(K₂/K₁) = 1/17 King, King (1/13) x (1/17) = 1/221

*************************************************************************************************

(ii) A deck of cards contains 4 Jacks, 4 Queens, & 4 Kings out of 52 total cards

1st draw: 12 Face cards out of 52 total cards → 12/52 = 3/13

2nd draw: 11 remaining Face cards out of 51 total remaining cards → 11/51

1st Draw 2nd Draw Outcome Probability

Face: P(F) = 3/13 Face: P(F₂/F₁) = 11/51 Face,Face (3/13) x (11/51) = 11/221

*************************************************************************************************

(iiI) A deck of cards contains 26 black cards out of 52 total cards but there are 2 black Jacks, 2 black Queens, and 2 black Kings.

1st draw: 20 Black (not Face) cards out of 52 total cards → 20/52 = 5/13

2nd draw: 19 remaining Black (not Face) cards out of 51 total remaining cards → 19/51

1st Draw 2nd Draw Outcome Probability

Black: P(B~) = 5/13 Black: P(B~₂/B~₁) = 19/51 B~,B~ (5/13) x (19/51) = 95/663

*************************************************************************************************

(ii) A deck of cards contains 4 Aces out of 52 total cards

1st draw: 4 Aces out of 52 total cards → 4/52 = 1/13

2nd draw: 1 Queen of Hearts out of 51 total remaining cards → 1/51

1st Draw 2nd Draw Outcome Probability

Ace: P(A) = 1/13 Qh: P(Qh₂/A₁) = 1/51 Ace,Queen(h) (1/13) x (1/51) = 1/663

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