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Oxana [17]
2 years ago
11

PLEASE HELP ILL GIVE BRAIN

Mathematics
1 answer:
stiv31 [10]2 years ago
3 0

Answer:

Step-by-step explanation:

15. (-4-3)/(-5-0)= -7/-5= 7/5

      y - 3 = 7/5x - 0

      y = 7/5x + 3

16. (-2-3)/(4-0)= -5/4

     y - 3 = -5/4x - 0

     y = -5/4x + 3

17. (-3+5)/(0+3)= 2/3

    y + 5 = 2/3(x + 3)

     y + 5 = 2/3x + 2

     y = 2/3x - 3

18. (-2-2)/(0+4)= -4/4= -1

       y - 2 = -1(x + 4)

       y - 2 = -x - 4

       y = -x - 2

19. y - 3 = 1/2x - 0

     y = 1/2x + 3

20. y - 2 = -(x + 1)

      y - 2 = -x - 1

      y = -x + 1

21. perp. -5/3

y + 5 = -5/3x  + 0

 y = -5/3x - 5

22. perp. 1/2

   y + 1 = 1/2(x + 4)

   y + 1 = 1/2x + 2

   y = 1/2x + 1

23. perp. 3/4

   y + 5 = 3/4(x + 4)

   y + 5 = 3/4x + 3

   y = 3/4x - 2

24. perp. 7/5

 y - 4 = 7/5(x - 5)

 y - 4 = 7/5x - 7

 y = 7/5x - 3

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Answer:

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Read 2 more answers
Customers arrive at a movie theater at the advertised movie time only to find that they have to sit through several previews and
balu736 [363]

Answer:

(a) The sample size required is 43.

(b) The sample size required is 62.

Step-by-step explanation:

The (1 - α) % confidence interval for population mean is:

 CI=\bar x\pm z_{\alpha/2}\ \frac{\sigma}{\sqrt{n}}

The margin of error for this interval is:

 MOE=z_{\alpha/2}\ \frac{\sigma}{\sqrt{n}}

(a)

The information provided is:

<em>σ</em> = 4 minutes

MOE = 72 seconds = 1.2 minutes

Confidence level = 95%

α = 5%

Compute the critical value of z for α = 5% as follows:

 z_{\alpha/2}=z_{0.05/2}=z_{0.025}=1.96

*Use a z-table.

Compute the sample size required as follows:

 MOE=z_{\alpha/2}\ \frac{\sigma}{\sqrt{n}}

       n=[\frac{z_{\alpha/2}\times \sigma}{MOE} ]^{2}

          =[\frac{1.96\times 4}{1.2}]^{2}\\\\=42.684\\\\\approx 43

Thus, the sample size required is 43.

(b)

The information provided is:

<em>σ</em> = 4 minutes

MOE = 1 minute

Confidence level = 95%

α = 5%

Compute the critical value of z for α = 5% as follows:

 z_{\alpha/2}=z_{0.05/2}=z_{0.025}=1.96

*Use a z-table.

Compute the sample size required as follows:

 MOE=z_{\alpha/2}\ \frac{\sigma}{\sqrt{n}}

       n=[\frac{z_{\alpha/2}\times \sigma}{MOE} ]^{2}

          =[\frac{1.96\times 4}{1}]^{2}\\\\=61.4656\\\\\approx 62

Thus, the sample size required is 62.

3 0
3 years ago
What is the x-intercept for 12x+2=17y
ollegr [7]
12x+2=17y
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— —
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