Answer:
43 and 5
Step-by-step explanation:
Let's let the two unknown numbers be a and b.
Their sum is 48, therefore:

And their difference is 38. In other words:

We now have a system of equations. To solve, we can use substitution. First, add b to both sides in the second equation:

Substitute this into the first equation:

Combine like terms:

Subtract 38 from both sides:

Divide both sides by 2:

So, one of the numbers is 5.
The sum of them is 48. Therefore, the other number is 48-5 or 43.
So, our two numbers are 43 and 5.
And we're done!
Answer:
When the price of a ticket = $0 or $40, there will be no revenue.
The revenue will be $500 if each ticket cost $37.3 or $2.68
Step-by-step explanation:
Let R(p) = p(200-5p)
when R(p) = 0
p(200-5p) = 0
p = 0 or 200-5p = 0
When the price of a ticket = $0 or $40, there will be no revenue.
when R(p) = 500
200p - 5p² = 500
5p² - 200p + 500 = 0
p = $37.3 or $2.68 (3 sig. fig.)
The required prices are $37.3 and $2.68
So 12x 8+96 and you do 12 time 8 because x=12 and then 2x2 because y+4 and times by 2 because there is a 2 in front and that equals 8 and then 8x2 because z is 2 and add both sides =112
answer
112
10 xy + 3y + 20 ax + 6a = y(10x+3) + a(20x+6) = y(10x+3)+2a(10x+6)=
(y+2a)(10x+3)
0 or 1 or more than one for zero functions