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Vaselesa [24]
3 years ago
15

(x² + 6x − 16)(x − 2) = ax³ + bx² + cx + d

Mathematics
1 answer:
stellarik [79]3 years ago
3 0
B is the right answer to this question
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Which of the following is NOT a solution to the system of inequalities?
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(+,0)

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because the graph of the inequality

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What is 80 times 30 = plz help me
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80 x 30 = 2,400

Step-by-step explanation:

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What is true when the plane is 100 meters away from takeoff? Check all that apply. The given information is the SSS case. The gi
givi [52]

Two triangle are congruent when the shape and size of both the triangle are same. The given information is the SAS case.

To find the form of the case we need to know about the triangle congruence theorem.

<h3>What is triangle congruence theorem?</h3>

Two triangle are congruent when the shape and size of both the triangle are same.

Triangle congruence theorem are-

  • Angle-Side-Angle theorem (AAS)- This theorem states that two triangle is congruent when two angle and one side of the triangle are respectively equal to the two angles and same side of the other triangle.

  • Side-Side-Side theorem (SSS)- When the three sides of the one triangle is equal to the three sides of the other triangle respectively, then the triangle are congruent.

  • Side-Angle-Side theorem (SAS)- Two sides and the included angle of are equal to the two sides and one angle of other triangle respectively.

Given information-

Evelyn is 104 meters from the take off.

The angle of elevation of the plane is 12°.

The plane is 100 meters away from the takeoff point.

The distance is 100 meters and 104 meters. The other two sides , as are same and the angle of elevation is also same for this case (12 degrees).

Thus the two triangle formed which are congruent.

As above discussed the case of SAS exists for the triangle congruence theorem.

Hence the given information is the SAS case.

Learn more about the triangle congruence theorem here;

brainly.com/question/19258025

4 0
2 years ago
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The bearing of a lighthouse from a ship is N 37° E. The ship sails 2.5 miles further from the lighthouse. The new bearing is 25°
djverab [1.8K]

Answer:

The distance between the ship at N 25°E and the lighthouse would be 7.26 miles.

Step-by-step explanation:

The question is incomplete. The complete question should be

The bearing of a lighthouse from a ship is N 37° E. The ship sails 2.5 miles further towards the south. The new bearing is N 25°E. What is the distance between the lighthouse and the ship at the new location?

Given the initial bearing of a lighthouse from the ship is N 37° E. So, \angle ABN is 37°. We can see from the diagram that \angle ABC would be 180-37= 143°.

Also, the new bearing is N 25°E. So, \angle BCA would be 25°.

Now we can find \angle BAC. As the sum of the internal angle of a triangle is 180°.

\angle ABC+\angle BCA+\angle BAC=180\\143+25+\angle BAC=180\\\angle BAC=180-143-25\\\angle BAC=12

Also, it was given that ship sails 2.5 miles from N 37° E to N 25°E. We can see from the diagram that this distance would be our BC.

And let us assume the distance between the lighthouse and the ship at N 25°E is AC=x

We can apply the sine rule now.

\frac{x}{sin(143)}=\frac{2.5}{sin(12)}\\ \\x=\frac{2.5}{sin(12)}\times sin(143)\\\\x=\frac{2.5}{0.207}\times 0.601\\ \\x=7.26\ miles

So, the distance between the ship at N 25°E and the lighthouse is 7.26 miles.

3 0
3 years ago
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