Question:
Zach tries to solve an equation step by step;
![\frac{3}{4} = z - \frac{1}{2}](https://tex.z-dn.net/?f=%5Cfrac%7B3%7D%7B4%7D%20%3D%20z%20-%20%5Cfrac%7B1%7D%7B2%7D)
Step 1:
![\frac{3}{4} + \frac{1}{2} = z - \frac{1}{2} + \frac{1}{2}](https://tex.z-dn.net/?f=%5Cfrac%7B3%7D%7B4%7D%20%2B%20%5Cfrac%7B1%7D%7B2%7D%20%3D%20z%20-%20%5Cfrac%7B1%7D%7B2%7D%20%2B%20%5Cfrac%7B1%7D%7B2%7D)
Step 2:
![\frac{3}{4} + \frac{1}{2} = z](https://tex.z-dn.net/?f=%5Cfrac%7B3%7D%7B4%7D%20%2B%20%5Cfrac%7B1%7D%7B2%7D%20%3D%20z)
![\frac{5}{4} = z](https://tex.z-dn.net/?f=%5Cfrac%7B5%7D%7B4%7D%20%3D%20z)
Find Zach's mistake;
Answer:
Zach didn't make any mistake
Step-by-step explanation:
Given: the steps above
At step 1, he applied addition property of equality by adding
to both sides of the equation
Step 2 is a result of step 1 and he rightly added the fractions
Further Explanation;
![\frac{3}{4} = z - \frac{1}{2}](https://tex.z-dn.net/?f=%5Cfrac%7B3%7D%7B4%7D%20%3D%20z%20-%20%5Cfrac%7B1%7D%7B2%7D)
Add
to both sides
![\frac{3}{4} + \frac{1}{2} = z - \frac{1}{2} + \frac{1}{2}](https://tex.z-dn.net/?f=%5Cfrac%7B3%7D%7B4%7D%20%2B%20%5Cfrac%7B1%7D%7B2%7D%20%3D%20z%20-%20%5Cfrac%7B1%7D%7B2%7D%20%2B%20%5Cfrac%7B1%7D%7B2%7D)
![\frac{3}{4} + \frac{1}{2} = z](https://tex.z-dn.net/?f=%5Cfrac%7B3%7D%7B4%7D%20%2B%20%5Cfrac%7B1%7D%7B2%7D%20%3D%20z)
Take LCM of fractions at the left hand side
![\frac{3 + 2}{4} = z](https://tex.z-dn.net/?f=%5Cfrac%7B3%20%2B%202%7D%7B4%7D%20%3D%20z)
![\frac{5}{4} = z](https://tex.z-dn.net/?f=%5Cfrac%7B5%7D%7B4%7D%20%3D%20z)
Reorder
![z = \frac{5}{4}](https://tex.z-dn.net/?f=z%20%3D%20%5Cfrac%7B5%7D%7B4%7D)
<em>Analyzing the steps one after the other, we can conclude that Zach didn't make any mistake;</em>
Answer:
? = 105
Step-by-step explanation:
Use similar triangles and law of proportions.
?/56 = 120/64
?/56 = 15/8
8 * ? = 56 * 15
? = 7 * 15
? = 105
Answer:
Step-by-step explanation:
we know that
The compound interest formula is equal to
where
A is the Final Investment Value
P is the Principal amount of money to be invested
r is the rate of interest in decimal
t is Number of Time Periods
n is the number of times interest is compounded per year
in this problem we have
substitute in the formula above
Distribute -5.5(2-6x) first
-5.5 x 2 = -11 & -5.5 x -6x =33x
=> 33x - 11
33x - 11 -2.5x
subtract common like terms
33x - 2.5x = 30.5x
Answer: 30.5x -11
Take S(x^2+5)-(x^2)dx from 2 to 4
=S5dx=5x from 2 to 4
=5*4-5*2=20-10=10