Question

hauler and gio went to the store. they each purchased pop and snacks. hailey purchased 1 pop and 4 snacks and spent $14. gio purchased 2 pops and 2 snacks and spent $10. how much did the store charge each pop and snack? (write a system of equations and use elimination to solve.)

Answer 1

Answer:

Cost of pop = $2

Cost of snacks = $3

Step-by-step explanation:

Let

Cost of pop = x

Cost of snacks = y

Hauler

x + 4y = 14

Good

2x + 2y = 10

x + 4y = 14 (1)

2x + 2y = 10 (2)

Using elimination method

Multiply (1) by (2)

2x + 8y = 28 (3)

2x + 2y = 10 (2)

Subtract (2) from (3) to eliminate x

8y - 2y = 28 - 10

6y = 18

y = 18/6

y = $3

Substitute y = 3 into (1)

x + 4y = 14 (1)

x + 4(3) = 14

x + 12 = 14

x = 14 - 12

x = $2

Cost of pop = $2

Cost of snacks = $3