Question 1 (1 point) Question 1 Unsaved

Maru [420]

First, we have to understand the slope-intercept form.

$\large \boxed{y = mx + b}$

A linear function/equation has three forms and the slope-intercept is one of the form. It is also commonly used in Function topic while the other two forms are commonly used in Analytic Geometry.

In the slope-intercept form, the m-term represents the slope while b-term represents the y-intercept of a graph.

Which equation represents a linear function that has a slope of 5 and a y-intercept of -6.

As you notice the bold, italic and underlined words in the question that I quoted or rewrote. I've just explained that the slope is m-term and y-intercept is b-term.

Therefore, substitute m = 5 and b = -6 in the equation.

$\large{y = mx + b \longrightarrow \bold{y = 5x + ( - 6)}} \\ \large \boxed{ \tt{ \purple{y = 5x - 6}}}$

I hope this helps! Let me know if you have any questions regarding the linear function, don't hestitate to ask. Good luck with your assignment and have a nice day!

5 0

2 years ago

Express the sum of the polymonial 3x^2+15x-56 and the square of the binomial (x-8) as a polynomial in standard form.

tester [92]

Given:

Polynomial is $3x^2+15x-56$ .

To find:

The sum of given polynomial and the square of the binomial (x-8) as a polynomial in standard form.

Solution:

The sum of given polynomial and the square of the binomial (x-8) is

$3x^2+15x-56+(x-8)^2$

$=3x^2+15x-56+x^2-2(x)(8)+8^2$ $[\because (a-b)^2=a^2-2ab+b^2]$

$=3x^2+15x-56+x^2-16x+64$

On combining like terms, we get

$=(3x^2+x^2)+(15x-16x)+(-56+64)$

$=4x^2-x+8$

Therefore, the sum of given polynomial and the square of the binomial (x-8) as a polynomial in standard form is $4x^2-x+8$ .

7 0

3 years ago

Solve the inequality 5(2h+8)<60

zimovet [89]

Answer:

Step-by-step explanation:

5(2h+8) < 60

Expand the terms in the bracket

We have

10h + 40 < 60

Group like terms

10h < 60 - 40

10h < 20

Divide both sides by 10

h < 2

Hope this helps you

7 0

3 years ago

What is the equation of the line in slope-intercept form? y=_x+_

tangare [24]

Answer:

$y=\frac{4}{3}x+4$

Step-by-step explanation:

4 0

3 years ago

<img src="https://tex.z-dn.net/?f=5x%5E%7B2%7D%2B%7Cx%2B1%7C%5C%20%5Ctextgreater%20%5C%200" id="TexFormula1" title="5x^{2}+|x+1|

Pavel [41]

5x² + |x+1| > 0
5x² + x + 1 > 0
x+1 > 0 because it came from absolute
5x² > 0 because it’s squared

When you try a number you should put it in the original equality
5x² + |x+1|

7 0

2 years ago