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kirza4 [7]
2 years ago
7

Geoff wants to make a 100 ml of 5% alcohol solution mixing a quantity of a 2% alcohol solution with a 7% alcohol solution. What

are the quantities of each of the two solutions (2% and 7%) he has to use?
____ ml of the 2% solution

____ ml of the 7% solution
Mathematics
1 answer:
Paha777 [63]2 years ago
7 0

Answer:

3

Step-by-step explanation:

753

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Write the following equation in sentence form: 2H (g) + O (g) → 2H₂O (l)
Sav [38]

Answer:

2 molecule of hydrogen+oxygen=water

5 0
3 years ago
Can someone please help me with this question:)
AlladinOne [14]

Answer:

x = 12 and y = 24 Can I get brainiiest

Step-by-step explanation:

We know (3x + 34) and (2x + 46) are vertical to each other so they equal the same measure. We will solve it like this.

3x + 34 = 2x + 46 (subtract 34 on each side)

3x = 2x + 12 (subtract 2x on both sides)

x = 12

Now plug in

3(12) + 34 = 2(12) + 46

36 + 34 = 24 + 46

70 = 70

Now all you have to do is do the other pair of angle

4y + 14 + 70 = 180 (we are using what we already know about 70)

(collect like terms)

4y + 84 = 180 (subtract 84 on both sides)

4y = 76 (divide by 4)

y = 24

(plug in)

4(24) + 14 = 6(24) - 34

96 + 14 = 144 - 34

110 = 110

5 0
3 years ago
32) Find the value of 5x° + 2x-1 when x = 4.
SashulF [63]

Answer:

5x4°x7

Step-by-step explanation:

5x°+2x-1 when x =4

5x4°+2x4-1

5x4°+8-1

=5x4°x7

5 0
3 years ago
4 consecutive odd integers add up to -200. Find the integers.
Alexeev081 [22]
Let
x = first odd integer
x + 2 = second odd integer
x + 4 = third odd integer
x + 6 = fourth odd integer

x + (x + 2) + (x + 4) + (x + 6) = -200
4x = -200 - 2 - 4 - 6
4x = -212
x = -53

Therefore, the four consecutive integers are -53, -51, -49, -47.
4 0
3 years ago
Find lim x→3 sqrt 2x+3-sqrt 3x/ x^2-3x. you must show your work or explain your work in words plsss I need help
sineoko [7]

I'm assuming the limit is supposed to be

\displaystyle\lim_{x\to3}\frac{\sqrt{2x+3}-\sqrt{3x}}{x^2-3x}

Multiply the numerator by its conjugate, and do the same with the denominator:

\left(\sqrt{2x+3}-\sqrt{3x}\right)\left(\sqrt{2x+3}+\sqrt{3x}\right)=\left(\sqrt{2x+3}\right)^2-\left(\sqrt{3x}\right)^2=-(x-3)

so that in the limit, we have

\displaystyle\lim_{x\to3}\frac{-(x-3)}{(x^2-3x)\left(\sqrt{2x+3}+\sqrt{3x}\right)}

Factorize the first term in the denominator as

x^2-3x=x(x-3)

The x-3 terms cancel, leaving you with

\displaystyle\lim_{x\to3}\frac{-1}{x\left(\sqrt{2x+3}+\sqrt{3x}\right)}

and the limand is continuous at x=3, so we can substitute it to find the limit has a value of -1/18.

7 0
3 years ago
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