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3 years ago

What is 20/36 reduced

Mathematics

2 answers:

likoan [24]3 years ago

7 0

20/36 reduced is 5/9. hope this helped! :)

natka813 [3]3 years ago

5 0

5/9
Hope this helps!!!1

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Let X be the waiting time for a car to pass by on a country road, where X has an average value of 35 minutes. If the random vari

Gelneren [198K]

Answer:

Probability that the wait time is greater than 37 minutes is 0.3474.

Step-by-step explanation:

We are given that the random variable X is known to be exponentially distributed and X be the waiting time for a car to pass by on a country road, where X has an average value of 35 minutes.

<u><em>Let X = waiting time for a car to pass by on a country road</em></u>

The probability distribution function of exponential distribution is given by;

$f(x) = \lambda e^{-\lambda x} , x >0$ where, $\lambda$ = parameter of distribution.

Now, the mean of exponential distribution is = $\frac{1}{\lambda}$ which is given to us as 35 minutes that means $\lambda = \frac{1}{35}$ .

So, X ~ Exp( $\lambda = \frac{1}{35}$ )

Also, we know that Cumulative distribution function (CDF) of Exponential distribution is given as;

$F(x) = P(X \leq x) = 1 - e^{-\lambda x}$ , x > 0

Now, Probability that the wait time is greater than 37 minutes is given by = P(X > 37 min) = 1 - P(X $\leq$ 37 min)

P(X $\leq$ 37 min) = $1 - e^{-\frac{1}{35} \times 37}$ {Using CDF}

= 1 - 0.3474 = 0.6525

So, P(X > 37 min) = 1 - 0.6525 = 0.3474

Therefore, probability that the wait time is greater than 37 minutes is 0.3474.

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3 years ago

Please I truly need help I’m not that good with math

m_a_m_a [10]

Answer:

the answer is A

Step-by-step explanation:

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3 years ago

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Softa [21]

Answer:

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3 years ago

Read 2 more answers

Software to detect fraud in consumer phone cards tracks the number of metropolitan areas where calls originate each day. It is f

pashok25 [27]

Answer:

0.999987

Step-by-step explanation:

Given that

The user is a legitimate one = E₁

The user is a fraudulent one = E₂

The same user originates calls from two metropolitan areas = A

Use Bay's Theorem to solve the problem

P(E₁) = 0.0131% = 0.000131

P(E₂) = 1 - P(E₁) = 0.999869

P(A/E₁) = 3% = 0.03

P(A/E₂) = 30% = 0.3

Given a randomly chosen user originates calls from two or more metropolitan, The probability that the user is fraudulent user is :

$P(E_2/A)=\frac{P(E_2)\times P(A/E_2)}{P(E_1)\times P(A/E_1)+P(E_2)\times P(A/E_2)}$

$=\frac{(0.999869)(0.3)}{(0.000131)(0.03)+(0.999869)(0.3)}$

$\frac{0.2999607}{0.00000393+0.2999607}$

$\frac{0.2999607}{0.29996463}$

= 0.999986898 ≈ 0.999987

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3 years ago

Traveling with the current, a boat covers a distance 1.5 times greater than traveling against the current in the same amount of

jeka94

Let the speed of the current equal c
and the speed of the boat in still water equal b.

b + c = 1.5 (b - c)
b + c = 1.5b - 1.5c
0.5b = 2.5c
b = 5c

The speed of the current is 1.5 mph so
b = 5 * 1.5 = 7.5 mph

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3 years ago