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PolarNik [594]
3 years ago
12

Help please on quiz !!

Mathematics
1 answer:
vesna_86 [32]3 years ago
5 0

Answer: 3.15

Step-by-step explanation:

21 / 15%

You might be interested in
Molly runs each morning once around a circular path in her neighborhood. if the diameter of the path is 1.4 miles, how far does
Lemur [1.5K]
To work out the distance of the path, you need to find out the circumference.
Formula for circumference = pi multiplied by the diameter

So you simply do:
pi multiplied by 1.4 miles

And you should get:
4.39822971503... miles

Simply round the result to an appropriate value (e.g. 3 decimal places).

Answer: 4.398 miles (to 3dp)
Hope the answer helps :)
6 0
3 years ago
Evaluate (8+2)³-6?<br> Please help
tatiyna

Answer:

994 :)

Step-by-step explanation:

PEMDAS

(8+2)^3 - 6

(10)^3   = 10 x 10 x 10

1,000    - 6

994

3 0
2 years ago
Boxes of raisins are labeled as containing 22 ounces. Following are the weights, in the ounces, of a sample of 12 boxes. It is r
ZanzabumX [31]

Answer:

A 90% confidence interval for the mean weight is [21.78 ounces, 21.98 ounces].

Step-by-step explanation:

We are given the weights, in the ounces, of a sample of 12 boxes below;

Weights (X): 21.88, 21.76, 22.14, 21.63, 21.81, 22.12, 21.97, 21.57, 21.75, 21.96, 22.20, 21.80.

Firstly, the pivotal quantity for finding the confidence interval for the population mean is given by;

                         P.Q.  =  \frac{\bar X-\mu}{\frac{s}{\sqrt{n} } }  ~ t_n_-_1

where, \bar X = sample mean weight = \frac{\sum X}{n} = 21.88 ounces

            s = sample standard deviation = \sqrt{\frac{\sum (X-\bar X)^{2} }{n-1} }  = 0.201 ounces

            n = sample of boxes = 12

            \mu = population mean weight

<em>Here for constructing a 90% confidence interval we have used a One-sample t-test statistics because we don't know about population standard deviation.</em>

<u>So, 90% confidence interval for the population mean, </u>\mu<u> is ;</u>

P(-1.796 < t_1_1 < 1.796) = 0.90  {As the critical value of t at 11 degrees of

                                                  freedom are -1.796 & 1.796 with P = 5%}  

P(-1.796 < \frac{\bar X-\mu}{\frac{s}{\sqrt{n} } } < 1.796) = 0.90

P( -1.796 \times {\frac{s}{\sqrt{n} } } < {\bar X-\mu} < 1.796 \times {\frac{s}{\sqrt{n} } } ) = 0.90

P( \bar X-1.796 \times {\frac{s}{\sqrt{n} } } < \mu < \bar X+1.796 \times {\frac{s}{\sqrt{n} } } ) = 0.90

<u>90% confidence interval for</u> \mu = [ \bar X-1.796 \times {\frac{s}{\sqrt{n} } } , \bar X+1.796 \times {\frac{s}{\sqrt{n} } } ]

                                        = [ 21.88-1.796 \times {\frac{0.201}{\sqrt{12} } } , 21.88+1.796 \times {\frac{0.201}{\sqrt{12} } } ]

                                        = [21.78, 21.98]

Therefore, a 90% confidence interval for the mean weight is [21.78 ounces, 21.98 ounces].

8 0
3 years ago
If someone can answer this and explain it, I would really appreciate it, thanks.
daser333 [38]

Answer:

x = 13

Step-by-step explanation:

Now since the lines are parrarel, the intersection points are alternate to each other. Therefore, A = B.

Solve:

8x + 2 = 14x - 76

2 + 76 = 6x

78 = 6x

x = 13

8 0
3 years ago
Read 2 more answers
Please solve for M&lt;QTR​
Andru [333]

Answer:

m∠QTR = 98°

Step-by-step explanation:

From the picture attached,

Radii of the circle are TQ and TR measuring equal lengths.

Therefore, ΔTQR is a isosceles triangle.

Opposite angles of the equal sides will be equal in measure.

m∠RQT = m∠TRQ = 41°

By angle sum theorem,

m∠RQT + m∠TRQ + m∠QTR = 180°

41° + 41° + m∠QTR = 180°

m∠QTR = 180° - 82°

              = 98°

Therefore, m∠QTR = 98°

7 0
2 years ago
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