Answer: a. 0.6759 b. 0.3752 c. 0.1480
Step-by-step explanation:
Given : The long-distance calls made by the employees of a company are normally distributed with a mean of 6.3 minutes and a standard deviation of 2.2 minutes
i.e. 
minutes
minutes
Let x be the long-distance call length.
a. The probability that a call lasts between 5 and 10 minutes will be :-
b. The probability that a call lasts more than 7 minutes. :
![P(X>7)=P(\dfrac{X-\mu}{\sigma}>\dfrac{7-6.3}{2.2})\\\\=P(Z>0.318)\ \ \ \ [z=\dfrac{X-\mu}{\sigma}]\\\\=1-P(Z](https://tex.z-dn.net/?f=P%28X%3E7%29%3DP%28%5Cdfrac%7BX-%5Cmu%7D%7B%5Csigma%7D%3E%5Cdfrac%7B7-6.3%7D%7B2.2%7D%29%5C%5C%5C%5C%3DP%28Z%3E0.318%29%5C%20%5C%20%5C%20%5C%20%5Bz%3D%5Cdfrac%7BX-%5Cmu%7D%7B%5Csigma%7D%5D%5C%5C%5C%5C%3D1-P%28Z%3C0.318%29%5C%5C%5C%5C%3D1-0.6248%5C%20%5C%20%5C%20%5C%20%5B%5Ctext%7Bby%20z-table%7D%5D%5C%5C%5C%5C%3D0.3752)
c. The probability that a call lasts more than 4 minutes. :
Answer:
<u>2x⁵ + x⁴ - x³ + 6x² + 3x - 3</u>
Step-by-step explanation:
Given :
- f(x) = x³ + 3
- g(x) = 2x² + x - 1
Finding (f × g)(x) :
- f(x) × g(x)
- (x³ + 3)(2x² + x - 1)
- 2x⁵ + 6x² + x⁴ + 3x - x³ - 3
- <u>2x⁵ + x⁴ - x³ + 6x² + 3x - 3</u>
A.360 / 25= 14.4
B. 480 / 32= 15
B Is getting better mileage
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Answer:
$5.47
Step-by-step explanation:
Given data:
Annie has 4 dollar , 11 dimes, 4 pennies.
Tommy has 3 dimes, 3 pennies.
To add the money, let us first convert dime and penny into dollar.
1 dollar = $1
11 dime = $1.1
4 penny = $0.04
3 dime = $0.3
3 penny = $ 0.03
Total money = Annie’s money + Tommy’s money
= $4 + $1.1 + $ 0.04 + $0.3 + $0.03
= $5.47
So, they have $5.47 in all.
Answer:
I guess option c is the answer
