Answer:
32.176 ft/s²
9.807 m/s²
Explanation:
Data provided in the question:
Acceleration of the free falling object = 78979.4 mi/hr²
a) In ft/s
Now,
1 mi = 5280 foot
and,
1 hour = 3600 seconds
thus,
78979.4 mi/hr = ![\frac{\textup{78979.4}\times\textup{5280}}{\textup{1}\times\textup{3600}^2}](https://tex.z-dn.net/?f=%5Cfrac%7B%5Ctextup%7B78979.4%7D%5Ctimes%5Ctextup%7B5280%7D%7D%7B%5Ctextup%7B1%7D%5Ctimes%5Ctextup%7B3600%7D%5E2%7D)
or
78979.4 mi/hr = 32.176 ft/s² ...............(1)
b) In m/s²
Now,
1 foot = 0.3048 m
thus,
we have from 1
32.17 ft/s² = ![\frac{\textup{32.17}\times\textup{0.3048}}{\textup{1}\times\textup{1}^2}](https://tex.z-dn.net/?f=%5Cfrac%7B%5Ctextup%7B32.17%7D%5Ctimes%5Ctextup%7B0.3048%7D%7D%7B%5Ctextup%7B1%7D%5Ctimes%5Ctextup%7B1%7D%5E2%7D)
or
78979.4 mi/hr = 32.176 ft/s² = 9.807 m/s²
Answer:
0.25 cm³.
Explanation:
We shall apply Boyle's law to find the solution . According to it
PV = constant where P is pressure and V is volume of the gas.
P₁ V₁ = P₂V₂
1 x .5 = 2 x V₂
V₂ = 0.25 cm³.
Answer: my ecosystem
Explanation:the ecosystem I want to live in is one with nature that you can eat witch tastes good and with animals that you can talk to. I would love to live in an ecosystem like that.
Answer:
distance between the charges is 5.12 × 10⁶ m
Explanation:
charges q₁ = -130.0 C
q₂ = 180 C
force between the charges = 8 N
force between two charge
![F = \dfrac{k q_1q_2}{r^2}](https://tex.z-dn.net/?f=F%20%3D%20%5Cdfrac%7Bk%20q_1q_2%7D%7Br%5E2%7D)
value of K =8.975 × 10⁹ N.m²/C²
![8 = \dfrac{8.975 \times 10^{9}\times 130 \times 180}{r^2}](https://tex.z-dn.net/?f=8%20%3D%20%5Cdfrac%7B8.975%20%5Ctimes%2010%5E%7B9%7D%5Ctimes%20130%20%5Ctimes%20180%7D%7Br%5E2%7D)
![r^2 = \dfrac{8.975 \times 10^{9}\times 130 \times 180}{8}](https://tex.z-dn.net/?f=r%5E2%20%3D%20%5Cdfrac%7B8.975%20%5Ctimes%2010%5E%7B9%7D%5Ctimes%20130%20%5Ctimes%20180%7D%7B8%7D)
r = 5.12 × 10⁶ m
hence, distance between the charges is 5.12 × 10⁶ m.
Answer:
3.011 x 10^23 molecules
Explanation:
- Mass of Sulphuric (H2SO4) = 49g
-
We have the number of molecules in 49g of H2SO4
Molecular mass of H2SO4 = (Atomic mass of H) x 2 + (Atomic mass of S) x 1 + (Atomic mass of O) x 4
= ( 1 x 2) + (32 x 1) + (16 x 4)
= 2 + 32 + 64
= 98.
Now,
- According to the formula,
Number of moles in the given H2SO4(n) = Mass of H2SO4 in grams/Molecular mass of H2SO4
= 49/98
= 1/2
= 0.5
: n = 0.5 mol
- 1 mol of H2SO4 contains 6.022 x 10^23 molecules.
-
0.5 mol of H2SO4 contains 0.5 x 6.022 x 10^23 molecules.
= 3.011 x 10^23 molecules .
that is 49 g of H2SO4 contains 3.011 x 10^23 molecules of H2SO4.