Answer:
20ln(3)
Step-by-step explanation:
Put 15 for A and solve for t.
15 = 45e^(-.05t)
15/45 = 1/3 = e^(-.05t) . . . . divide by 45
ln(1/3) = -.05t . . . . . . . . . . . take natural logs
20ln(3) = t . . . . . . . . . . . . . . multiply by 20, simplify
It will take 20·ln(3) years for the area to decrease to 15 km^2.
<span>System 1 and system 2, because the second equation in system 2 is obtained by adding the first equation in system 1 to two times the second equation in system 1
This is the correct answer because not only is it true but it also follows the property of solving systems of equations with adding the equations. To prove that it is true:
2nd equation in system #2 = 1st equation in system #1 + 2(2nd equation in system #1)
</span>10x − 7y = 18 == 4x − 5y = 2 + 2(<span>3x − y = 8)
10x - 7y = 18 == 4x - 5y = 2 + 6x - 2y = 16
10x = 7y = 18 == 10x - 7y = 18</span>
9514 1404 393
Answer:
yes
Step-by-step explanation:
The constant ratio (23 mi)/(1 gal) tells you the number of miles is a linear function of the number of gallons.
miles = (miles/gallon) × gallons
miles = constant × gallons . . . . . a linear function of gallons
Answer:
It would be (3,2) since it is being reflected over the line it is already on
Step-by-step explanation:
