Answer:
The area of the region is 25,351
.
Step-by-step explanation:
The Fundamental Theorem of Calculus:<em> if </em>
<em> is a continuous function on </em>
<em>, then</em>

where
is an antiderivative of
.
A function
is an antiderivative of the function
if

The theorem relates differential and integral calculus, and tells us how we can find the area under a curve using antidifferentiation.
To find the area of the region between the graph of the function
and the x-axis on the interval [-6, 6] you must:
Apply the Fundamental Theorem of Calculus



From least to Greatest: 8/100, 7/10, 3/5
Answer:
42.8 + or - 12
Step-by-step explanation:
He's either gaining or losing $12 so you can write 42.8 plus or minus 12 as the equation
Team A scored a total of 80,597 points I believe
161,161 + 33 = 161,194
161,194 ÷2 = 80,597
80,597- 33 = 80,564
80,564 + 80,597 = 161,161
Answer:
221
Step-by-step explanation:
2 - 1 + 5 · 4 · 11 = 2 - 1 + 20 · 11 = 2 - 1 + 220
2 - 1 + 220 = 1 + 220