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Hoochie [10]
2 years ago
8

Solve this pls thank you

Mathematics
1 answer:
Nana76 [90]2 years ago
5 0

Answer:21

Step-by-step explanation:9+10=21

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What fraction of a circle is 80°?​
Liono4ka [1.6K]

Answer:

2/9

Step-by-step explanation:

Simplify 80°/360°

4 0
3 years ago
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Use the geometric mean to find the 7th term in a geometric sequence if the 6th term is 12 and the 8th term is 27. 20 19.5 18 17
Lesechka [4]
A₆ =12

a₇ = ?? = x

a₈ 27

In this case x is the geometric mean & as per the formula
geometric mean of 2 numbers =√(a₆ * a₈) = √(12*27)
& x=18.
Proof:
Find the common ratio between a₇ & a₆ ==> = ( x) / 12
now find the common ration between a₈ & a₇ ===> =27 / (x)
x/12 = 27/x ===> x² = 12*27 ==> x² = 324 & x =√324 = 18
7 0
3 years ago
Lee's family had a garden in the shape of a right triangle. the total area of the garden is 16 square feet. if they expand the g
lana [24]
Area of right-angled triangle  is given by;

Area, A = 1/2 *b*h, Where b=base, h=height

Therefore,

A1 = 1/2bh = 16 in^2
A2 = 1/2 (2b)(2h) = 2bh

Ratio of increase = A2/A1 = {2bh}/(1/2bh} = 4 (the area is increased 4 times)
The,
A2 = 4*16 = 64 in^2
Therefore,
The area is increased by (64-16) = 48 in^2
5 0
3 years ago
(urgent please help!!!!)in computing the mean of 8 numbers, a student mistakenly used 17 instead of 25 as one of the numbers and
mamaluj [8]
I believe the correct mean is 21!
6 0
3 years ago
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A ball is thrown upward from ground level. Its height h, in feet, above the ground after t seconds is h-48t -16t^2.
Marat540 [252]

Answer:

36 feet.

Step-by-step explanation:

We have been given that a ball is thrown upward from ground level. Its height h, in feet, above the ground after t seconds is h(t)=-48t -16t^2. We are asked to find the maximum height of the ball.

We can see that our given equation is a downward opening parabola, so its maximum height will be the vertex of the parabola.

To find the maximum height of the ball, we need to find y-coordinate of vertex of parabola.

Let us find x-coordinate of parabola using formula x=-\frac{b}{2a}.

x=-\frac{-48}{2(-16)}

x=-\frac{48}{32}

x=-\frac{3}{2}

So, the x-coordinate of the parabola is -\frac{3}{2}. Now, we will substitute x=-\frac{3}{2} in our given equation to find y-coordinate of parabola.

h(t)=-48t -16t^2

h(-\frac{3}{2})=-48(-\frac{3}{2})-16(-\frac{3}{2})^2

h(-\frac{3}{2})=-24(-3)-16(\frac{9}{4})

h(-\frac{3}{2})=72-4*9

h(-\frac{3}{2})=72-36

h(-\frac{3}{2})=36

Therefore, the maximum height of the ball is 36 feet.

3 0
3 years ago
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