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3 years ago

Pls solve this it is math no scams ty

Mathematics

2 answers:

lozanna [386]3 years ago

8 0

Answer:

The 3rd one (x < -4)

Step-by-step explanation:

Feliz [49]3 years ago

6 0

Answer: $x>-4$

Step-by-step explanation:

<em>Take the inequality</em>

<em /> $6x-5>-29\\ +5 +5\\6x> 5-29\\6x>-24\\Divide\\\frac{6x}{6}>\frac{-24}{6}\\x>-4$ <em />

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What is the arc length of the arc sub tended in a circle with radius 6 and an angle of 7 pi/ 8

KengaRu [80]

Answer:

Formula for the Arc length is given by:

$\text{Arc length} = 2 \pi r \cdot \frac{\theta}{360^{\circ}}$

As per the statement:

radius of circle(r) = 6 units

Angle ( $\theta$ ) = $\frac{7 \pi}{8}$ radian

Use conversion:

$1 rad = \frac{180}{\pi}$

$\frac{7 \pi}{8}$ = $\frac{180}{\pi} \cdot \frac{7 \pi}{8} = \frac{1260}{8} = 157.5^{\circ}$

then;

substitute these given values we have;

Use value of $\pi = 3.14$

$\text{Arc length} = 2\cdot 3.14 \cdot (6) \cdot \frac{157.5^{\circ}}{360^{\circ}}$

$\text{Arc length} = 2\cdot 3.14 \cdot (6) \cdot 0.4375$

Simplify:

$\text{Arc length}=16.485$

Therefore, the arc length of the arc substended in a circle with radius 6 units an angle of 7 pi/8 is 16.485 units

7 0

3 years ago

Pleasee anwser fast!!

KIM [24]

Answer:

its 4 bv 1x4 is 4 4x4 is 16 and 16x4 is 64! goodluck!

6 0

2 years ago

K-20/5=11j ; solve for k

yan [13]

In terms of j: 55j+20 = k

4 0

3 years ago

Read 2 more answers

A probability experiment is conducted in which the sample space of the experiment is upper s equals startset 4 comma 5 comma 6 c

olchik [2.2K]

The correct question statement is:

A probability experiment is conducted in which the sample space of the experiment is S = {4,5,6,7,8,9,10,11,12,13,14,15}. Let event E={7,8,9,10,11,12,13,14,15}. Assume each outcome is equally likely. List the outcomes in $E^{c}$ . Find $P(E^{c})$ .

Solution:

Part 1:

$E^{c}$ means compliment of the set E. A compliment of a set can be obtained by finding the difference of the set from the universal set. The universal set is the set which contains all the possible outcomes of the events which is S in this case.

So, compliment of E will be equal to S - E. S - E will result in all those elements of S which are not present in E. So, we can write:

$E^{c}=S-E \\ \\ 
E^{c}=(4,5,6,7,8,9,10,11,12,13,14,15)-(7,8,9,10,11,12,13,14,15) \\ \\ 
E^{c}=(4,5,6)$

Thus the set compliment of E will contain the elements {4,5,6}.So

$E^{c}$ = {4,5,6}

Part 2)

$P(E^{c})$ means probability that if we select any number from the Sample Space S, it will belong the set E compliment.

$P(E^{c})$ = (Number of Elements in $E^{c}$ )/Number of elements in S

Number of elements in set S = n(S) = 12
Number of elements in set $E^{c}$ = $n(E^{c})$ =3

So,

$P(E^{c})= \frac{n(E^{c}) }{n(S)} \\ \\ 
P(E^{c})= \frac{3}{12} \\ \\ 
P(E^{c})= \frac{1}{4}$

7 0

3 years ago

Sean bought 1.8 pounds of gummy bears and 0.6 pounds of jelly beans and paid $10.26. He went back to the store the following wee

Ymorist [56]

Answer:

Gummy bears $3.20/lbs

Jelly beans $7.50/lbs

Step-by-step explanation:

For this we will substitute gummy bear price for "x" and jelly bean price for "y" which creates this system (also assuming there is no sales tax involved):

1.8x + 0.6y = 10.26

1.2x + 1.5y = 15.09

Then once solved, answers come out to be (x,y) = (16/5,15/2) which is (3.2,7.5)

7 0

2 years ago