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Dima020 [189]
3 years ago
9

Pls solve this it is math no scams ty

Mathematics
2 answers:
lozanna [386]3 years ago
8 0

Answer:

The 3rd one (x < -4)

Step-by-step explanation:

Feliz [49]3 years ago
6 0

Answer: x>-4

Step-by-step explanation:

<em>Take the inequality</em>

<em />6x-5>-29\\     +5   +5\\6x> 5-29\\6x>-24\\Divide\\\frac{6x}{6}>\frac{-24}{6}\\x>-4<em />

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Answer:

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The perimeter of a triangle is 50 mm. The lengths of 2 of the sides are 13.5 mm and 14.5 mm. Find the missing length.
Naddik [55]
The missing side length should be 22. Add 13.5 to 14.5 and you should get 28. Subtract 28 from the total perimeter (50) to get 22.
5 0
2 years ago
If a = 5^x, b = 5^y and a^y×b^x = 25 then prove that: xy =1​
avanturin [10]

a =  {5}^{x}  \\ b =  {5}^{y}  \\  {a}^{y}  \times  {b}^{y}  = 25 \\ prove \: ( {5}^{x} )^{y}  \times ( {5}^{y} ) ^{x}  = 25 \\  {5}^{xy}  \times  {5}^{yx}  = {5}^{2} \\  {5 }^{xy + yx}  = 5^{2}  \\ 5^{2xy}  =  {5}^{2} \\ is \:  \: 2xy = 2 \\ xy =  \frac{2}{2}  \\ xy = 1

3 0
3 years ago
I will mark you the brainiest for the correct answer, please be correct, Have a good day and take care, thanks. ( VIEW THE IMAGE
makkiz [27]

Mistake in Line 2 : Was in the determining the values for a ,b,c

Mistake in Line 4 : Not taking the square roots of both sides.

Step-by-step explanation:

{a}^{2}  +  {b}^{2}  =  {c}^{2}

First Mistake : Line 2

a = x \\ b = 6 \\ c = 10

Second Mistake : Line 4

136 =  {x}^{2}  \\ not \\ 136 = x

Correct Solution :

{x}^{2}  +  {6}^{2}  =  {10}^{2}  \\  {x}^{2}  =  {10}^{2}  -  {6}^{2}  \\  {x}^{2}  = 100 - 36 \\

{x}^{2}  = 64 \\  \sqrt{ {x}^{2} }  =  \sqrt{64}  \\ x = 6

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3 years ago
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Sever21 [200]
<span>$7.89525 Would be the exact amount of taxed owed. Which rounds to $7.90</span>
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2 years ago
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