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Solnce55 [7]
2 years ago
9

How do i find the median in this question.

Mathematics
1 answer:
Korolek [52]2 years ago
4 0

eu9ewg0u8wei08

Step-by-step explanation:

jiwfoiqwfqeoufhqeio0hfqifh0qoio

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Which statements about the hyperbola are true? Check all that apply. There is a vertex at (–5, 2). The center of the hyperbola i
skelet666 [1.2K]

Answer:

A, B, E,

Step-by-step explanation:

CAuse yes

4 0
3 years ago
Read 2 more answers
Help me to prove the given below. Thank you in advance
sleet_krkn [62]

Answer:

Construct MO, where O is the midpoint of CG. (As shown in the attached figure)

(1) LM = MG //given, CM is the median to the hypotenuse      

(2) CO = OG // construction    

(3) MO is a mid-segment   //(1), (2) , Definition of a mid-segment

(4) MO // LC //triangle mid-segment theorem    

(5) ∠MOG ≅ ∠LCO // corresponding angles in two parallel lines intersected by a transversal line (CG)

(6) m∠LCO=90°  //given, ΔLCG is a right triangle

(7) m∠MOG=90° //(5), (6), definition of congruent angles

(8) m∠MOC=180° – 90° = 90° // linear pair

(9) ∠MOG ≅ ∠MOC //(7),(8), definition of congruent angles

(10) MO=MO //common side, reflexive property of equality  

(11) ΔMCO ≅ ΔMGO  //(2), (9), (10) Side-Angle-Side postulate

(12) MC = MG // Corresponding sides in congruent triangles (CPCTC)      

(13) MG= ½LG // Given, CM is the median to the hypotenuse    

(15) MC = ½LG //(12) , (13), substitution  

8 0
3 years ago
Solve using algebraic equation: <br> 5sin2x=3cosx<br><br> (No exponents)
DaniilM [7]
5\sin2x=3\cos x\iff10\sin x\cos x=3\cos x

by the double angle identity for sine. Move everything to one side and factor out the cosine term.

10\sin x\cos x=3\cos x\iff10\sin x\cos x-3\cos x=\cos x(10\sin x-3)=0

Now the zero product property tells us that there are two cases where this is true,

\begin{cases}\cos x=0\\10\sin x-3=0\end{cases}

In the first equation, cosine becomes zero whenever its argument is an odd integer multiple of \dfrac\pi2, so x=\dfrac{(2n+1)\pi}2 where n[/tex ]is any integer.\\Meanwhile,\\[tex]10\sin x-3=0\implies\sin x=\dfrac3{10}

which occurs twice in the interval [0,2\pi) for x=\arcsin\dfrac3{10} and x=\pi-\arcsin\dfrac3{10}. More generally, if you think of x as a point on the unit circle, this occurs whenever x also completes a full revolution about the origin. This means for any integer n, the general solution in this case would be x=\arcsin\dfrac3{10}+2n\pi and x=\pi-\arcsin\dfrac3{10}+2n\pi.
6 0
3 years ago
Someone pls help me with this im new thats why tysm if you do help!!:)
Kipish [7]

Answer:

-8 hope this helps

Step-by-step explanation:

7 0
3 years ago
Please help me i'll give 20 points to whoever helps me answer all 4 of them and brainly
Brilliant_brown [7]

Answer:

G - number of arrangements

F. the amount of her allowance

B. y = x

H. the number of hours

7 0
2 years ago
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