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AleksandrR [38]
3 years ago
15

Newton's second law in physics states that F=ma, where F is the force of an object (measured in Newtons), m is the mass of the o

bject (in kilograms) and a is the acceleration of that object (measured in m/s). Calculate the force created from an object with a mass of 640 grams and an acceleration of 10 m/s2
​
Mathematics
1 answer:
JulijaS [17]3 years ago
5 0

Answer:

mass=640/1000kg

=0.64kg

acceleration =10m/s^2

now,

force=mass*acceleration

=0.64*10

=6.4newton

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The weight of 100 identical samples of a substance is 1 pound. 
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4 years ago
Bethany is working her way through school. She works two part-time jobs for a total of 30 hours a week. Job A pays $5.90 per hou
Vikentia [17]

Answer:

13 hours at Job B, and 17 hours at Job A.

Step-by-step explanation:

13×7.20= 93.60

17×5.90=100.30

100.30+93.60= 193.90

3 0
3 years ago
NEED TO KNOW THIS QUESTION PLEASE!!!!
Westkost [7]

Answer:

15 units = h

Step-by-step explanation:

formula to find the volume is:

V = (l·w·h) ÷ 3

675 = (9)(15)h ÷ 3

675 = 135h ÷ 3

multiply each side by 3 to get:

2025 = 135h

2025/135 = h

15 = h

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3 years ago
A salesperson is driving from the office to a client, a distance of about 250 kilometers. After 45 minutes, the salesperson pass
ludmilkaskok [199]
<span> <span>Speed is calculated as distance covered, divided by the time taken to cover that distance. In this case, the sales person covered 50KM in 45minutes (which can also be expressed as 3/4 hours). To calculate the speed he used to cover this distance, we divide the distance covered by the time taken. So 50km/3/4hours. This gives us 66.67km/hr. In order to calculate the amount of time the salesperson used to travel from the office to the sales person, we calculate as follows 250km/66.67km/hr. This gives us a total of 3.75 hours or 3 hours 45 minutes.</span></span>
7 0
4 years ago
QRST is a square. PQ = 2√ RU = 4<br> What is the length of SU? Round to the nearest tenth.
777dan777 [17]

Answer:

SU=3.5\ units

Step-by-step explanation:

step 1

In the isosceles right triangle PQT

PQ=PT ----> because is an isosceles triangle

Applying the Pythagoras Theorem

we have

PQ=PT =\sqrt{2}\ units

QT^{2}=PQ^{2} +PT^{2}

substitute the values

QT^{2}=\sqrt{2}^{2} +\sqrt{2}^{2}

QT^{2}=4

QT=2\ units

step 2

In the square QRST

RS=QT=2\ units

step 3

In the right triangle RSU

Applying the Pythagoras Theorem

RU^{2}=RS^{2} +SU^{2}

we have

RU=4\ units

RS=2\ units

substitute the values and solve for SU

4^{2}=2^{2} +SU^{2}

SU^{2}=4^{2}-2^{2}

SU^{2}=12

SU=2\sqrt{3}\ units

SU=3.5\ units

8 0
3 years ago
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