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konstantin123 [22]

3 years ago

10

The rectangle shown has a perimeter of 54 cm and the given area. Its length is 3 more than 3 times its width. Write and solve a

system of equations to find the dimensions of the rectangle.
The length of the rectangle is what cm ?
the width of the rectangle is
what cm.?

1 answer:

algol133 years ago

5 0

Answer:

Step-by-step explanation:

the perimeter P=2(L+W)=54

P=2L+2W=54 OR L+W=27

we know that L=3W+3

P=3W+W=27-3

4W=24

W=6 CM

L=21CM

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Please solve this for me using substitution

Vinvika [58]

<h2> <u>Explanation</u><u>:</u></h2>

$\bf \underline{★Given-} \\$

$\textsf{4x + 5y = 8};$

$\textsf{5x + 4y = 12}$

$\bf \underline{★To\: find-} \\$

$\textsf{the value of x and y in equation?}$

$\bf \underline{★Solution-} \\$

$\sf \leadsto 4x + 5y = 8 - - - (i)$

$\sf \leadsto 5x + 4y = 12 - - - (ii)$

By first equation,

$\sf \leadsto 4x + 5y = 8$

$\sf \leadsto 4x = 8 - 5y$

$\sf \leadsto x = \dfrac{8 - 5y}{4}$

$\textsf{Now, we can find the original value of Y.}\\$

$\sf \leadsto 5x + 4y = 12$

$\sf \leadsto 5 \bigg( \dfrac{8 - 5y}{4} \bigg) + 4y = 12$

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$\sf \leadsto \dfrac{40 - 25y + 16y}{4} = 12$

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$\sf \leadsto 40 - 9y = 12(4)$

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$\textsf{Now, we can find the original value of X.}\\$

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$\sf \leadsto \dfrac{36x - 40}{9} = 8$

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$\underline{\textsf{Answer-}}\\$

Therefore, the values of x and y are -8/9 and 112/36 respectively.

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http://www.1728.org/radians.htm

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