The space diagonal will have length ...
... d = √(1² +4² +2²) = √(1 +16 +4) = √21
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This can be found using the Pythagorean theorem. A drawing can help. Find the length of any face diagonal, then use that length as the leg of a right triangle whose hypotenuse is the space diagonal and whose other leg is the edge length not used in the first calculation.
Answer:
Step-by-step explanation:
Not sure what form you need this in, but it really doesn't matter, as you'll see in the final equation. I used the vertex form and solved for a:
We are given the vertex (h, k) as the origin (0, 0), and we have a point that the graph goes through as (4, -64). That's our x and y. Plugging in what we have:
gives us
-64 = 16a and
a = -4. That means that the quadratic equation is
which is both vertex form and standard form here, no difference.
Answer:
- B. The probability that the student received a grade better than C is 0.45
Step-by-step explanation:
<u>Total number of students:</u>
- 15 + 30 + 35 + 16 + 4 = 100
<h3>Statements</h3>
A.
- p(<D) = 4/100 = 0.04
- 0.04 ≠ 0.2
- Incorrect
B.
- p(>C) = (30 + 15)/100 = 45/100 = 0.45
- 0.45 = 0.45
- Correct
C.
- p(not A or B) = (100 - 15 - 30)/100 = 55/100 = 0.55
- 0.55 ≠ 0.45
- Incorrect
D.
- p(B or C) = (30 + 35)/100 = 65/100 = 0.65
- 0.65 ≠ 0.35
- Incorrect
<u>Answer:</u>
0.0005 oz
<u>Step-by-step explanation:</u>
Usually, the greatest number that is allowed for approximation, assuming that the number itself is obtained by approximation, is the greatest possible error of it.
It is normally half the place value of the last digit in a number.
Like here we have 
oz which is equal to 
oz. The last digit is 5 which is at the thousandth place (0.001) so the greatest possible error for this would be its half.
= 0.0005 oz
Answer:
25m
Step-by-step explanation:
