Answer:
Therefore the required polynomial is
M(x)=0.83(x³+4x²+16x+64)
Step-by-step explanation:
Given that M is a polynomial of degree 3.
So, it has three zeros.
Let the polynomial be
M(x) =a(x-p)(x-q)(x-r)
The two zeros of the polynomial are -4 and 4i.
Since 4i is a complex number. Then the conjugate of 4i is also a zero of the polynomial i.e -4i.
Then,
M(x)= a{x-(-4)}(x-4i){x-(-4i)}
=a(x+4)(x-4i)(x+4i)
=a(x+4){x²-(4i)²} [ applying the formula (a+b)(a-b)=a²-b²]
=a(x+4)(x²-16i²)
=a(x+4)(x²+16) [∵i² = -1]
=a(x³+4x²+16x+64)
Again given that M(0)= 53.12 . Putting x=0 in the polynomial
53.12 =a(0+4.0+16.0+64)
=0.83
Therefore the required polynomial is
M(x)=0.83(x³+4x²+16x+64)
Answer:
y=-9x-4
Step-by-step explanation:
Perpendicular lines meet the following condition:
m2*m1= -1 (a)
where m is the slope of a line
m1 is given through equation of line 1, y =1/9 x+2
m2 must be -9 -> from eq. (a)
The Line has the following equation: y=mx+b, where m=-9 and the b is the interception with y axis.
Evaluating the above equation in (-1,5) we have the following equation
5= -9*(-1)+b, we have b=-4
The line has the following equation
y=-9x-4
Slope intercept form
Answer:
y=17
Step-by-step explanation:4(y+8)=100
We move all terms to the left:
4(y+8)-(100)=0
We multiply parentheses
4y+32-100=0
We add all the numbers together, and all the variables
4y-68=0
We move all terms containing y to the left, all other terms to the right
4y=68
y=68/4
y=17
Answer:
eggs milk baking soda sugar butter
Square root of 11 because:
sqrt2^2 = 2
3^2 = 9
so C^2 or the hypotenuse would be the square root of 11
