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3 years ago

Find the equation of quadratic function with (6,-2) and (5,-5)

Mathematics

1 answer:

aliina [53]3 years ago

3 0

Answer:

y= 3(x-5)^2-5 is the equation.

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State the reason why MN = LK.

Fudgin [204]

I hope this helps you

5 0

2 years ago

Please answer fast

Levart [38]

Answer:

Yes it is

Step-by-step explanation:

Because

2) x (sqrt 3) times (sqrt 12)

Two is also equivalent to sqrt of 4. The operation may be expressed as,

(sqrt 4) x (sqrt 3) x sqrt (12)

The product is sqrt (144). This gives an answer of 12 and it is rational.

So, the answer is Yes!

Hope this helped! :)

May i have brainliest!

8 0

3 years ago

If the mean of a set of 12 number is 13 then the sum of the number is?

rjkz [21]

Answer:

156

Step-by-step explanation:

Let the sum of the set of numbers = S

So....the mean would be calculated as the sum of the set divided by its number of entries, or :

S / 12 = 13 ....... multiply both sides by 12

S = 13 * 12 = 156 .....so.....the sum is 156

5 0

3 years ago

For Triangle ABC, what is the length of AB?

Stels [109]

The length of AB is 5 units

4 0

2 years ago

Read 2 more answers

A circle has a radius of 3 feet. A bigger circle is created so that has a ratio of radii is 4:7 with the smaller circle. What is

Margaret [11]

Answer:

$\boxed{\textsf{ The ratio of the circumference of two circles is \textbf{ 4:7}.}}$

Step-by-step explanation:

Given that the circle has a radius of 3 feet . And a bigger circle is created so that the ratio of radii of the two circles is 4 : 7 . And we need to find the ratio of the circumferences .

Now we know that the circumference of the circle is given by ,

$\qquad\boxed{\boxed{\sf Circumference_{(circle)}= 2\pi r }}$

Now let the circumference of the first circle be $\sf C_1$ and the circumference of the second circle be $\sf C_2$ .

Finding the ratios :-

$\sf\implies C_1:C_2 = 2\pi r_1 : 2\pi r_2\\\\\sf\implies \dfrac{C_1}{C_2}= \dfrac{2\pi r_1}{2\pi r_2}\\\\\sf\implies \dfrac{C_1}{C_2}= \dfrac{2\pi }{2\pi } \times \dfrac{r_1}{r_2}\\\\\sf\implies \dfrac{C_1}{C_2}= \dfrac{4}{7} \\\\\sf:\implies \boxed{\pink{\frak{ C_1:C_2= 4:7}}}$

Hence the ratio of the circumferences is same as that of the radius .

4 0

3 years ago